storage_make_public.py

#!/usr/bin/env python

# Copyright 2019 Google Inc. All Rights Reserved.
#
# Licensed under the Apache License, Version 2.0 (the 'License');
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
#     http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.

import sys

# [START storage_make_public]
from google.cloud import storage


def make_blob_public(bucket_name, blob_name):
    """Makes a blob publicly accessible."""
    # bucket_name = "your-bucket-name"
    # blob_name = "your-object-name"

    storage_client = storage.Client()
    bucket = storage_client.bucket(bucket_name)
    blob = bucket.blob(blob_name)

    blob.make_public()

    print(
        f"Blob {blob.name} is publicly accessible at {blob.public_url}"
    )


# [END storage_make_public]

if __name__ == "__main__":
    make_blob_public(bucket_name=sys.argv[1], blob_name=sys.argv[2])