[misterhouse-users] re: Getting close on power watch circuit

Alan,
Well to change the output direction you should only have to swap pins 5 =
and 6 so that the output stage operates as an inverter. However from =
your description it is not operating as I expected ( I expected the =
output to go high when the light was shone on the sensor) so I may be =
wrong on this. Perhaps someone else can explain it to me. Could the IC =
be damaged?
The other way of changing it is to swap over the sensor and the 10k =
resistor.
Also it is not really meant to drive a LED, so it might be an idea to =
increase the LED resistor to 1k which will make your output low lower.
Baz

Alan Womack  wrote,
>I need to change my output from being high, dropped low, to being low =
brought
>high so that the DS1994 iButton will register the over 5v condition as =
a pulse.

>What changes do I need to make to the circuit for this? The iButton =
needs to
>see a low signal inorder for the bus to be read by the DS9097U.