C Program For Int to Char Conversion

To convert the int to char in C language, we will use the following 2 approaches:

1. Using typecasting
2. Using sprintf()

Example:

Input:  N = 65
Output: A

1. Using Typecasting

Method 1:

• Declaration and initialization: To begin, we will declare and initialize our integer with the value to be converted.
• Typecasting: It is a technique for transforming one data type into another. We are typecasting integer N and saving its value in the data type char variable c.
• Print the character: Finally, print the character using print.

Example:

// C program to demonstrate
// conversion of int to char
// using typecasting
#include <stdio.h>

// Driver code
int main()
{
    int N = 103;
    printf("%c", (char)(N));
    return 0;
}

g

Time complexity is O(1)

The auxiliary is also O(1)

Method 2:

• Declaration and initialization: To begin, we will declare and initialize our integer with the value to be converted.
• Typecasting: Declare another variable as character c and assign the value of N to the C
• Print the character: Finally, print the character using printf.

Example:

// C program to demonstrate conversion of
// int to char using typecasting
#include <stdio.h>

// Driver code
int main()
{
    int N = 71;
    char c = N;
    printf("%c", c);
    return 0;
}

G

2. Using sprintf()

Allot space for a single int variable that will be converted into a char buffer.

Example:

// C program to demonstrate conversion of
// int to char using sprintf()
#include <stdio.h>
int main()
{
    int num = 71;
    char c[1];

    sprintf(c, "%c", num);
    printf("The character value is %s", c);

    return 0;
}

The character value is G

Method: Converting to int to char by adding 0 

#include <stdio.h>

// Driver code
int main()
{
    int N = 71;
    char c = N+0;
    printf("%c", c);
    return 0;
}

G

Method:

#include <stdio.h>

int main() 
{
    int num=71;
    if (num >= 0 && num <= 127) {
        printf("The character representation of %d is: %c\n", num, num);
    } else {
        printf("The integer %d is out of range for character representation\n", num);
    }
    return 0;
}