Natural numbers include all positive integers from 1 to infinity. There are multiple methods to find the sum of natural numbers and here, we will see how to find the sum of natural numbers using recursion.

Example
Input : 5
Output : 15
Explanation : 1 + 2 + 3 + 4 + 5 = 15Input : 10
Output : 55
Explanation : 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
Approach
- Given a number n,
- To calculate the sum, we will use a recursive function recSum(n).
- BaseCondition: If n<=1 then recSum(n) returns the n.
- Recursive call: return n + recSum(n-1).
Program to find the sum of Natural Numbers using Recursion
Below is the implementation using recursion:
// C program to find the sum of n
// natural numbers using recursion
#include <stdio.h>
// Returns the sum of first n
// natural numbers
int recSum(int n)
{
// Base condition
if (n <= 1)
return n;
// Recursive call
return n + recSum(n - 1);
}
// Driver code
int main()
{
int n = 10;
printf("Sum = %d ", recSum(n));
return 0;
}
Output
Sum = 55
The complexity of the above method
Time complexity: O(n).
Auxiliary space: O(n).