Output of the Program | Use Macros Carefully!

Predict the output of the below program  

#include <iostream>
using namespace std;

#define square(x) x*x

int main() 
{
  int x;
  x = 36 / square(6);
  
  cout << x;
  
  return 0;
}

// This code is contributed by sarajadhav12052009

#include <stdio.h>
#define square(x) x*x

int main()
{
  int x;
  x = 36/square(6);
  printf("%d",x);
 
  getchar();
  return 0;
}

36

Explanation: Preprocessor replaces square(6) by 6*6 and the expression becomes x = 36/6*6 and value of x is calculated as 36. If we want correct behavior from macro square(x), we should declare it as #define square(x) ((x)*(x)) /* Note that the expression (x*x) will also fail for square(6-2) */