Given a string, check if we can split it into 4 strings such that each string is non-empty and different from the other.
Examples:
Input : str[] = "geeksforgeeks"
Output : Yes
"geeks", "for", "gee", "ks" are four distinct strings that can form from given string.
Input : str[] = "aaabb"
Output : No
Try It Yourself
[Approach] Brute force - O(n^3) Time and O(n) Space
Observe if the length of the string is greater than or equal to 10, then every time can split into four parts. Suppose, the length is of 10, then string of length 1, 2, 3, 4 can be made. For string having length less than 10, we can use brute force i.e iterate through all possible ways of splitting the string and check each one.
#include<iostream>
using namespace std;
bool check(string s)
{
if (s.size() >= 10)
return true;
for (int i =1; i < s.size(); i++)
{
for (int j = i + 1; j < s.size(); j++)
{
for (int k = j + 1; k < s.size(); k++)
{
// Making 4 string from the given string
string s1 = s.substr(0, i);
string s2 = s.substr(i, j - i);
string s3 = s.substr(j, k - j);
string s4 = s.substr(k, s.size() - k);
// Checking if they are distinct or not.
if (s1 != s2 && s1 != s3 && s1 != s4 &&
s2 != s3 && s2 != s4 && s3 != s4)
return true;
}
}
}
return false;
}
int main()
{
string str = "aaabb";
(check(str))? (cout << "Yes" << endl):
(cout << "No" << endl);
return 0;
}
class GFG
{
// Return true if both strings are equal
public static boolean strcheck(String s1, String s2)
{
if (s1 != s2)
return false;
return true;
}
// Return if the given string can be split or not.
public static boolean check(String s)
{
if (s.length() >= 10)
return true;
for (int i = 1; i < s.length(); i++)
{
for (int j = i + 1; j < s.length(); j++)
{
for (int k = j + 1; k < s.length(); k++)
{
// Making 4 string from the given string
String s1 = "", s2 = "", s3 = "", s4 = "";
try
{
s1 = s.substring(0, i);
s2 = s.substring(i, j - i);
s3 = s.substring(j, k - j);
s4 = s.substring(k, s.length() - k);
}
catch (StringIndexOutOfBoundsException e) {
}
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
public static void main(String[] args)
{
String str = "aaabb";
if (check(str))
System.out.println("Yes");
else
System.out.println("No");
}
}
def check(s):
if (len(s) >= 10):
return True
for i in range(1, len(s)):
for j in range(i + 1, len(s)):
for k in range(j + 1, len(s)):
# Making 4 from the given
s1 = s[0:i]
s2 = s[i:j - i]
s3 = s[j: k - j]
s4 = s[k: len(s) - k]
# Checking if they are distinct or not.
if (s1 != s2 and s1 != s3 and s1 != s4 and
s2 != s3 and s2 != s4 and s3 != s4):
return True
return False
if __name__ == '__main__':
str = "aaabb"
print("Yes") if(check(str)) else print("NO")
using System;
class GFG
{
// Return if the given string
// can be split or not.
public static Boolean check(String s)
{
// We can always break a string of size 10 or
// more into four distinct strings.
if (s.Length >= 10)
return true;
for (int i = 1; i < s.Length; i++)
{
for (int j = i + 1; j < s.Length; j++)
{
for (int k = j + 1; k < s.Length; k++)
{
// Making 4 string from the given string
String s1 = s.Substring(0, i);
String s2 = s.Substring(i, j - i);
String s3 = s.Substring(j, k - j);
String s4 = s.Substring(k);
// Checking if they are distinct or not.
if (s1 != s2 && s1 != s3 && s1 != s4 &&
s2 != s3 && s2 != s4 && s3 != s4)
return true;
}
}
}
return false;
}
public static void Main(String[] args)
{
String str = "aaabb";
if (check(str))
Console.WriteLine("Yes");
else
Console.WriteLine("No");
}
}
function strcheck(s1, s2)
{
if (s1.localeCompare(s2) != 0)
return false;
return true;
}
// Return if the given string can be split or not.
function check(s)
{
if (s.length >= 10)
return true;
for (let i = 1; i < s.length; i++)
{
for (let j = i + 1; j < s.length; j++)
{
for (let k = j + 1; k < s.length; k++)
{
// Making 4 string from the given string
let s1 = "", s2 = "", s3 = "", s4 = "";
s1 = s.substring(0, i);
s2 = s.substring(i, i + j - i);
s3 = s.substring(j, j + k - j);
s4 = s.substring(k, k + s.length - k);
// Checking if they are distinct or not.
if (strcheck(s1, s2) && strcheck(s1, s3) &&
strcheck(s1, s4) && strcheck(s2, s3) &&
strcheck(s2, s4) && strcheck(s3, s4))
return true;
}
}
}
return false;
}
//Driver Code
let str = "aaabb";
if (check(str))
console.log("Yes");
else
console.log("No");
Output
No