Given an array of rational numbers, the task is to find the LCM of these numbers.
Examples:
Input : vect[] = {2/7, 3/14, 5/3}
Output : 30/1
Input : vect[] = {3/14, 5/3}
Output : 15/1
Input : vect[] = {3/4, 3/2}
Output : 3/2
First find the lcm of all numerator of rational number then find the gcd of all the denominator of rational number then divide lcm of all numerator/ gcd of all the denominator this the lcm of rational number's.
Formula:-
LCM of all the numerator of Rational number's
lcm = -----------------------------------------------
GCD of all the denominator of Rational number's
Implementation:
// CPP program to find LCM of given array
#include <bits/stdc++.h>
using namespace std;
// get lcm of two numbers
int LCM(int a, int b)
{
return (a * b) / (__gcd(a, b));
}
// Finds LCM of numerators
int lcmOfNumerator(vector<pair<int, int> > vect)
{
// calculate the lcm of all numerators
int lcm = vect[0].first;
for (int i = 1; i < vect.size(); i++)
lcm = LCM(vect[i].first, lcm);
// return all numerator lcm
return lcm;
}
// Get GCD of all the denominators
int gcdOfDemoninators(vector<pair<int, int> > vect)
{
// calculate the gcd of all the denominators
int gcd = vect[0].second;
for (int i = 1; i < vect.size(); i++)
gcd = __gcd(vect[i].second, gcd);
// return all denominator gcd
return gcd;
}
// find lcm of all the rational number
void lcmOfRationals(vector<pair<int, int> > vect)
{
// return the LCM of all numerator/ GCD of all
// denominator
cout << lcmOfNumerator(vect) << "/"
<< gcdOfDemoninators(vect);
}
// Driver code
int main()
{
vector<pair<int, int> > vect;
// give rational number 2/7, 3/14, 5/3
// make pair as a numerator and denominator
vect.push_back(make_pair(2, 7));
vect.push_back(make_pair(3, 14));
vect.push_back(make_pair(5, 3));
lcmOfRationals(vect);
return 0;
}
// JAVA program to find LCM of given array
import java.util.*;
class GFG
{
static class pair
{
int first, second;
public pair(int first, int second)
{
this.first = first;
this.second = second;
}
}
// get lcm of two numbers
static int LCM(int a, int b)
{
return (a * b) / (__gcd(a, b));
}
static int __gcd(int a, int b)
{
return b == 0? a:__gcd(b, a % b);
}
// Finds LCM of numerators
static int lcmOfNumerator(Vector<pair> vect)
{
// calculate the lcm of all numerators
int lcm = vect.get(0).first;
for (int i = 1; i < vect.size(); i++)
lcm = LCM(vect.get(i).first, lcm);
// return all numerator lcm
return lcm;
}
// Get GCD of all the denominators
static int gcdOfDemoninators(Vector<pair> vect)
{
// calculate the gcd of all the denominators
int gcd = vect.get(0).second;
for (int i = 1; i < vect.size(); i++)
gcd = __gcd(vect.get(i).second, gcd);
// return all denominator gcd
return gcd;
}
// find lcm of all the rational number
static void lcmOfRationals(Vector<pair> vect)
{
// return the LCM of all numerator/ GCD of all
// denominator
System.out.print(lcmOfNumerator(vect)+ "/"
+ gcdOfDemoninators(vect));
}
// Driver code
public static void main(String[] args)
{
Vector<pair> vect = new Vector<pair>();
// give rational number 2/7, 3/14, 5/3
// make pair as a numerator and denominator
vect.add(new pair(2, 7));
vect.add(new pair(3, 14));
vect.add(new pair(5, 3));
lcmOfRationals(vect);
}
}
// This code is contributed by Rajput-Ji
# Python program to find LCM of given array
import math
# get lcm of two numbers
def LCM(a, b):
return (a * b) // (math.gcd(a, b))
# Finds LCM of numerators
def lcmOfNumerator(vect):
# calculate the lcm of all numerators
lcm = vect[0][0]
for i in range(1, len(vect)):
lcm = LCM(vect[i][0], lcm)
# return all numerator lcm
return lcm
# Get GCD of all the denominators
def gcdOfDemoninators(vect):
# calculate the gcd of all the denominators
gcd = vect[0][1]
for i in range(1, len(vect)):
gcd = math.gcd(vect[i][1], gcd)
# return all denominator gcd
return gcd
# find lcm of all the rational number
def lcmOfRationals(vect):
# return the LCM of all numerator/ GCD of all
# denominator
print(lcmOfNumerator(vect), "/",
gcdOfDemoninators(vect), sep = "")
# Driver code
vect = []
# give rational number 2/7, 3/14, 5/3
# make pair as a numerator and denominator
vect.append((2, 7))
vect.append((3, 14))
vect.append((5, 3))
lcmOfRationals(vect)
# This code is contributed by SHUBHAMSINGH10
// C# program to find LCM of given array
using System;
using System.Collections.Generic;
class GFG
{
class pair
{
public int first, second;
public pair(int first, int second)
{
this.first = first;
this.second = second;
}
}
// get lcm of two numbers
static int LCM(int a, int b)
{
return (a * b) / (__gcd(a, b));
}
static int __gcd(int a, int b)
{
return b == 0? a:__gcd(b, a % b);
}
// Finds LCM of numerators
static int lcmOfNumerator(List<pair> vect)
{
// calculate the lcm of all numerators
int lcm = vect[0].first;
for (int i = 1; i < vect.Count; i++)
lcm = LCM(vect[i].first, lcm);
// return all numerator lcm
return lcm;
}
// Get GCD of all the denominators
static int gcdOfDemoninators(List<pair> vect)
{
// calculate the gcd of all the denominators
int gcd = vect[0].second;
for (int i = 1; i < vect.Count; i++)
gcd = __gcd(vect[i].second, gcd);
// return all denominator gcd
return gcd;
}
// find lcm of all the rational number
static void lcmOfRationals(List<pair> vect)
{
// return the LCM of all numerator/ GCD of all
// denominator
Console.Write(lcmOfNumerator(vect)+ "/"
+ gcdOfDemoninators(vect));
}
// Driver code
public static void Main(String[] args)
{
List<pair> vect = new List<pair>();
// give rational number 2/7, 3/14, 5/3
// make pair as a numerator and denominator
vect.Add(new pair(2, 7));
vect.Add(new pair(3, 14));
vect.Add(new pair(5, 3));
lcmOfRationals(vect);
}
}
// This code is contributed by 29AjayKumar
<script>
// JAVASCRIPT program to find LCM of given array
class pair
{
constructor(first, second)
{
this.first = first;
this.second = second;
}
}
// get lcm of two numbers
function LCM(a, b) {
return Math.floor((a * b) / (__gcd(a, b)));
}
function __gcd(a, b) {
return b == 0 ? a : __gcd(b, a % b);
}
// Finds LCM of numerators
function lcmOfNumerator(vect)
{
// calculate the lcm of all numerators
let lcm = vect[0].first;
for (let i = 1; i < vect.length; i++)
lcm = LCM(vect[i].first, lcm);
// return all numerator lcm
return lcm;
}
// Get GCD of all the denominators
function gcdOfDemoninators(vect)
{
// calculate the gcd of all the denominators
let gcd = vect[0].second;
for (let i = 1; i < vect.length; i++)
gcd = __gcd(vect[i].second, gcd);
// return all denominator gcd
return gcd;
}
// find lcm of all the rational number
function lcmOfRationals(vect) {
// return the LCM of all numerator/ GCD of all
// denominator
document.write(lcmOfNumerator(vect) + "/"
+ gcdOfDemoninators(vect));
}
// Driver code
let vect = [];
// give rational number 2/7, 3/14, 5/3
// make pair as a numerator and denominator
vect.push(new pair(2, 7));
vect.push(new pair(3, 14));
vect.push(new pair(5, 3));
lcmOfRationals(vect);
// This code is contributed by _SAURABH_JAISWAL
</script>
Output
30/1
Time Complexity: O(n log(min(v))), where v is the minimum element of vector
Auxiliary Space: O(1)
Please suggest if someone has a better solution which is more efficient in terms of space and time.