Successive differentiation is the process of differentiating a function repeatedly, as many times as required. The derivatives obtained at each stage are called successive derivatives or higher-order derivatives.
Uses of Successive Derivatives
- Expanding functions into series (e.g., Taylor or Maclaurin series)
- Solving and forming differential equations
- Studying the shape and behaviour of curves (e.g., slope, concavity, acceleration)
Notation
If f(x) is a function defined on a domain D:
- The derivative of y with respect to x is written as
\frac{dy}{dx} , f'(x), Dy, y', or y1. This is called the first derivative of y. - The derivative of
\frac{dy}{dx} is denoted as\frac{d^2y}{dx^2} , f''(x), D2y, y'', or y2. This is called the second derivative of y. - The derivative of
\frac{d^2y}{dx^2} is denoted as\frac{d^3y}{dx^3} , f'''(x), D3y, y''', or y3. This is called the third derivative of y.
Likewise, the nth derivative of y is denoted as
For example: y = x3, find the 3rd derivative of the equation.
- 1st derivative:
\frac{dy}{dx} =\frac{d}{dx} (x3) = 2x2- 2nd derivative:
\frac{d^2y}{dx^2} =\frac{d}{dx} (2x2) = 2. 2 x = 4x- 3rd derivative:
\frac{d^3y}{dx^3} =\frac{d}{dx} (4x) = 4
nth Derivatives for Some Standard Functions
Here we will discuss nth derivatives of some standard functions such as:
- nth derivative of eax
- nth derivative of xm
- nth derivative of (ax + b)m
- nth derivative of log(ax + b)
- nth derivative of sin(ax + b)
1) nth derivative of y = eax
y1 = eax, y2 = a2eax, y3 = a3eax..
yn = aneax --(1)
Differentiating both sides w.r.t x we get
- yn+1 = mn(memx)
- yn+1 = mn+1emx
Therefore by mathematical induction we can say that (1) is true for all integer n
yn = aneax
2) nth derivative of y = xm
y1 = mxm-1, y2 = m(m-1)xm-2 , y3 = m(m-1)(m-2)xm-3.
yn = m(m-1)(m-2)...(m-(n-1))xm-(n+1)
Modifying the equation by multiplying and dividing with (m-n)!, we get:
yn =
Differentiating both sides w.r.t x we get
yn+1 =
Therefore by mathematical induction we can say that (1) is true for all integer n
yn =
\frac{m!}{(m-n)!}x^{m-n}
3) nth derivative of y = (ax + b)m
y1 = ma(ax+b)m-1, y2 = m(m-1)a2(ax+b)m-2, y3 = m(m-1)(m-2)(a3(ax+b)m-3
yn =m(m-1)(m-2)....(m-(n-1))(an(ax+b)m-n--(1)
Differentiating both sides w.r.t x we get
yn+1 = m(m-1)(m-2)....(m-(n-1))(m-n)an+1(ax+b)m-(n+1)
Therefore by mathematical induction we can say that (1) is true for all integer n
Modifying the equation 1 by multiplying and dividing with (m-n)!, we get:
yn =
yn =
\frac{m!}{(m-n)!}a^n(ax+b)^{m-n}
4) nth derivative of y = log(ax + b)
y1 = a(ax+b)-1, y2 = (-1)a2(ax+b)-2, y3 = (-1)(-2)(a3(ax+b)-3
yn =(-1)(-2)....(-(n-1))(an(ax+b)-n--(1)
Differentiating both sides w.r.t x we get
yn+1 = (-1)(-2)....(-(n-1))(-n)an+1(ax+b)-(n+1)
yn and yn+1 is in the same form, therefore by mathematical induction we can say that (1) is true for all integers n.
yn = (-1)(-2)....(-(n-1))(an(ax+b)-n
yn = (-1)n-1an((n-1)! / (ax+b)n
5) nth derivative of y = sin(ax + b)
y1 = a.cos(ax + b) = a.cos(ax + b + π/2)
y2 = a2cos(ax + b + π/2) = a2sin(ax + b + 2π/2) ,
y3 =a3cos(ax + b + 2π/2) = a3sin(ax + b + 3π/2)
yn = ansin(ax + b + nπ/2) --(1)
Differentiating both sides w.r.t x we get
yn+1 = an+!sin(ax + b + (n+1)π/2)
yn and yn+1 is in the same form, therefore by mathematical induction we can say that (1) is true for all integers n.
yn = ansin(ax + b + nπ/2)
Summary Table for nth Derivatives
Given below is the summary of the nth derivatives of the functions menioned above:
Function | 1st derivative | nth derivative |
|---|---|---|
eax | y1 = eax | yn = aneax |
xm | y1 = mxm-1 | yn = |
(ax + b)m | y1 = ma(ax+b)m-1 | yn = |
log(ax + b) | y1 = a(ax+b)-1 | yn = (-1)n-1an((n-1)! / (ax+b)n |
sin(ax + b) | y1 = a.cos(ax + b + π/2) | yn = a.cos(ax + b + nπ/2) |
cos(ax+b) | y1 = a.cos(ax + b + π/2) | yn = an.cos(ax + b + nπ/2) |
eaxsin(bx + c) | y1 = reaxsin(bx + c + 𝛉) | yn = rneaxsin(bx + c + n𝛉) |
eaxcos(bx + c) | y1 = reaxcos(bx + c + 𝛉) | yn = rneaxcos(bx + c + n𝛉) |
1/(ax + b) | y1 = (-1)a(ax+b)-2 | yn = (-1)nn!an(ax+b)-(n+1) |
1/(ax+b)2 | y1 = (-2)a(ax+b)-3 | y2 = (-1)n(n+1)!an(ax+b)-(n+2) |
Practice Questions for Successive Differentiation
1. y = xmeax, find the nth derivative.
2. y = (1−x)−m (integer m≥1), find the nth derivative
3. y = 1/(x2 + a2), find the nth derivative.
4. Find the derivative of y = sin(ax).cos(ax) using Leibniz Rule.
5. Find the derivative of y = log(x).xm using Leibniz Rule.