GATE EC || MATHEMATICS ||DIFFERENTIAL EQUATIONS || PYQs

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Question 1

Match the application to appropriate numerical method.

Application

P1: Numerical integration

P2: Solution to a transcendental equation 

P3: Solution to a system of linear equations 

P4: Solution to a differential equation

Numerical Methods

M1: Newton-Raphson Method

M2: Runge-Kutta Method 

M3: Simpson’s 1/3 rule

M4: Gauss Elimination Method

  •  P1–M3, P2–M2, P3–M4, P4–M1

  • P1–M3, P2–M1, P3–M4, P4–M2


  • P1–M4, P2–M1, P3–M3, P4–M2


  • P1–M2; P2–M1, P3–M3, P4–M4

Question 2

Screenshot-2025-10-03-205045


  • Screenshot-2025-10-03-205132



  • Screenshot-2025-10-03-205138


  • Screenshot-2025-10-03-205146


  • Screenshot-2025-10-03-205152


Question 3

Screenshot-2025-10-03-210109


  • Screenshot-2025-10-03-210156


  • Screenshot-2025-10-03-210202


  • Screenshot-2025-10-03-210207


  • Screenshot-2025-10-03-210213


Question 4

Consider the hom

Screenshot-2025-10-03-210842

ogeneous ordinary differential equation

  • 5.24 to 5.26

Question 5

Screenshot-2025-10-03-211633


  •  Hyperbolas and Parabolas


  •  Hyperbolas and Circles


  • Parabolas and Circles 


  •  Circles and Hyperbolas

Question 6

Screenshot-2025-10-03-212425


  • 1

  • 1/e

  • 0

  • -1

Question 7

Screenshot-2025-10-03-212907


  • Screenshot-2025-10-03-213004


  • Screenshot-2025-10-03-213011


  • Screenshot-2025-10-03-213016


  • Screenshot-2025-10-03-213022


Question 8

Screenshot-2025-10-03-221027


  • Screenshot-2025-10-03-221035


  • Screenshot-2025-10-03-221045


  • Screenshot-2025-10-03-221102


  • Screenshot-2025-10-03-221112


Question 9

Screenshot-2025-10-03-221816


  •  ln|y – 1| = 0.5x2 + C and y = -1


  • ln|y – 1| = 2x2 + C and y = 1


  • ln|y – 1| = 2x2 + C and y = -1


  •  ln|y – 1| = 0.5x2 + C and y = 1


Question 10

Which one of the following is the general solution of the first order differential equation

Where x, y are real?


  • y = 1 + x + tan–1 (x +c), where c is constant.


  •  y = 1 + x + tan (x + c), where c is a constant

  • y = 1 –x + tan–1 (x + c), where c is a constant.


  • y = 1 – x + tan (x + c), where c is a constant.


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