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C++ Numeric::accumulate() function
The C++ std::complex::accumulate() function is used to calculate the sum or to perform other operations on the elements within a range. It takes three arguments: the starting and ending iterator and an initial value for the accumulation. By default, it will add the elements to the initial value, but a custom binary operation such as multiplication or subtraction can be provided as fourth argument.
Syntax
Following is the syntax for std::numeric::accumulate() function.
T accumulate (InputIterator first, InputIterator last, T init); or T accumulate (InputIterator first, InputIterator last, T init, BinaryOperation binary_op);
Parameters
- first, last − It indicates the iterators to the initial and final positions in a sequence.
- init − It is an initial value for the accumulator.
- binary_op − It is binary operation.
Return Value
It returns the result of accumulating all the values in the range [first,last) to init.
Exceptions
It throws if any of binary_op, the assignments or an operation on an iterator throws.
Data races
The locale object is modified.
Example 1
In the following example, we are going to consider the basic usage of the accumulate() function.
#include <iostream> #include <numeric> #include <vector> int main() { std::vector < int > x = {11,22,3}; int a = std::accumulate(x.begin(), x.end(), 0); std::cout << "Result : " << a << std::endl; }
Output
Output of the above code is as follows −
Result : 36
Example 2
Consider the following example, where we are going to make the product of the elements.
#include <iostream> #include <numeric> #include <vector> int main() { std::vector < int > a = {11,2,12}; int x = std::accumulate(a.begin(), a.end(), 1, std::multiplies < int > ()); std::cout << "Result : " << x << std::endl; }
Output
Following is the output of the above code −
Result : 264
Example 3
Let's look at the following example, where we are going to get the sum of the odd elements.
#include <iostream> #include <numeric> #include <vector> int main() { std::vector < int > a = {1,2,3,4,5}; int x = std::accumulate(a.begin(), a.end(), 0, [](int sum, int x) { return x % 2 != 0 ? sum + x : sum; }); std::cout << "Result : " << x << std::endl; }
Output
If we run the above code it will generate the following output −
Result : 9