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Java.io.RandomAccessFile.skipBytes() Method
Description
The java.io.RandomAccessFile.skipBytes(int n) method Attempts to skip over n bytes of input discarding the skipped bytes. This method may skip over some smaller number of bytes, possibly zero. This may result from any of a number of conditions; reaching end of file before n bytes have been skipped is only one possibility. This method never throws an EOFException. The actual number of bytes skipped is returned. If n is negative, no bytes are skipped.
Declaration
Following is the declaration for java.io.RandomAccessFile.skipBytes() method.
public int skipBytes(int n)
Parameters
n − The number of bytes to be skipped.
Return Value
This method returns the actual number of bytes skipped.
Exception
IOException − If an I/O error occurs.
Example
The following example shows the usage of java.io.RandomAccessFile.skipBytes() method.
package com.tutorialspoint; import java.io.*; public class RandomAccessFileDemo { public static void main(String[] args) { try { // create a new RandomAccessFile with filename test RandomAccessFile raf = new RandomAccessFile("c:/test.txt", "rw"); // write something in the file raf.writeUTF("Hello World"); // set the file pointer at 0 position raf.seek(0); // print the string System.out.println("" + raf.readUTF()); // set the file pointer at 0 position raf.seek(0); // attempt to skip 10 bytes and print the number of bytes skipped System.out.println("" + raf.skipBytes(10)); // print what is left after skipping System.out.println("" + raf.readLine()); // set the file pointer to position 8 raf.seek(8); // attempt to skip 10 more bytes and print the number of bytes skipped System.out.println("" + raf.skipBytes(10)); } catch (IOException ex) { ex.printStackTrace(); } } }
Assuming we have a text file c:/test.txt, which has the following content. This file will be used as an input for our example program −
ABCDE
Let us compile and run the above program, this will produce the following result −
Hello World 10 rld 5