- Aptitude - Home
- Aptitude - Overview
- Quantitative Aptitude
Aptitude - Pipes & Cisterns Online Quiz
Following quiz provides Multiple Choice Questions (MCQs) related to Pipes & Cisterns. You will have to read all the given answers and click over the correct answer. If you are not sure about the answer then you can check the answer using Show Answer button. You can use Next Quiz button to check new set of questions in the quiz.
Q 1 - Two funnels can fill a tank in 20 minutes and 30 minutes separately. On the off chance that both the channels are opened at the same time, then the tank will be filled in:
Answer : B
Explanation
Part filled by both pipes in 1 min. =(1/20+ 1/30)= 5/60 = 1/12 Time taken to fill the tank = 12 minutes
Q 2 - A pump can fill a tank with water in 2 hours. In light of a break in the tank, it takes 7/3 hours to fill the tank. The hole can discharge the filled tank in:
Answer : D
Explanation
Part filled by the pump in 1 hr = 1/2 Net part filled by the pump and leak in 1 hr = 3/7 Emptying work done by the leak in 1 hr= (1/2 - 3/7)= 1/14 Leak can empty the tank in 14 hours.
Q 3 - A funnel can discharge a tank in 40 minutes. A second pipe with distance across twice as much as that of the first is likewise joined with the tank to purge it. The two together can exhaust the tank in:
Answer : B
Explanation
A pipe with double diameter will take half time. So, the second pipe can empty the full tank in 20 min. Part emptied by both in 1 min. (1/40+ 1/20) = 3/40 Time taken to empty the full tank = 40/3 min.
Q 4 - Two funnels can fill a reservoir in 14hrs and 16 hrs. individually. The funnels are opened all the while and it is found that because of spillage in the last, 32 minutes additional are taken for the reservoir to be topped off. In the event that the storage is full, in what time would the release unfilled it?
Answer : D
Explanation
Work done by two pipes in 1 hr= (1/14+1/16)= 15/112 Total time taken by two pipes and leak in 1 hr= (112/15+32/60) hrs= 8 hrs. Work done by the leak in 1 hr = (15/112- 1/8) = 1/112 Hence, the leak will empty the full cistern in 112 hrs.
Q 5 - Two pipes A and B can fill a reservoir in 6 minutes and 7 minutes separately. Both the funnels are opened then again for 1 minute each. In what the reality of the situation will become obvious eventually fill the storage?
Answer : C
Explanation
Part filled by A in 1st min and B in 2nd min =(1/6+ 1/7 )= 13/42 Part filled by (A+B) working alternately in 6 min. (1/2 * 13/42*6) = 13/14 Remaining part = (1-13/14) = 1/14 It is now A's turn. 1/6 part is filled in 1 min. 1/14 part is filled in (6*1/14) min = 3/7 min. Total time taken = 45/7 min.
Q 6 - Three funnels A, B; C can fill a tank in 6 hours. In the wake of working at it together for 2 hours, C is shut and A and B can fill the remaining part in 7 hours. The quantity of hours taken by C alone to fill the tank is:
Answer : C
Explanation
Part filled by (A+B+c) in 2 hours= (1/6*2)=1/3 2/3 part is filled by (A+B) in 7 hours. Whole is filled by (A+B) in (7*3/2) hr=21/2hrs. Part filled by C in 1 hour = (1/6-2/21) = 3/42 = 1/14 ∴C alone can fill it in 14 hours.
Q 7 - A storage has a hole which would exhaust it in 8 hours. A tap is transformed on which concedes 6 liters a moment into the reservoir and it is currently purged in 12 hours. What number of liters does the reservoir hold?
Answer : D
Explanation
Part filled in 1 hour = (1/8- 1/12)= 1/24 Time taken to fill the cistern= 24 hours Water moved in it 24 hours = (6*60*24) = 8640 liters. Capacity of the cistern = 8640 liters.
Q 8 - A cistern has 3 pipes A, B and C. A and B can ill it in 3 hours and 4 hours respectively while C can empty the completely filled cistern in 1 hour. If the pipes are opened in order at 3, 4 and 5 pm respectively, at what time will the cistern be empty?
Answer : A
Explanation
In 2 hours Pipe A will fill = 2/3 tank In 1 hour Pipe B will fill = 1/4 tank Part of tank filled till 5 PM = (2/3) + (1/4) = 11/12 Remaining part = 1 - (11/12) = 1/12 Net part emptied when A, b and C are opened = (1/3) +( 1/4) - 1 = (4+3-12)/12 = -5/12 ∴ 5/12 part is emptied in 1 hour. ∴ 11/12 is emptied in (12/5)*(11/12) = 11/5 = 2 hr 12 min ∴ Tank will be emptied at 7:12 PM.
Q 9 - A pump can fill a tank with water in 2 hours. Because of a leak in the tank, it takes 7/3 hours to fill the tank. The leak can empty the filled tank in?
Answer : D
Explanation
Part of the tank filled by the pump in 1 hour = 1/2 Part of the tank filled by the pump in 1 hour because of the leak = 3/7 ∴ Part of the tank emptied by the leak in 1 hour = 1/2 - 3/7 = 1/14 ∴ Leak will empty the tank in 14 hours.
Q 10 - Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for 1 hour each alternatively, the tank will be full in -
Answer : D
Explanation
Tank filled by (A+B) in 1 hour = (1/12 + 1/15) = 3/20 Tank filled by (A+C) in 1 hr = (1/12 + 1/20) = 2/15 ∴ Part of tank filled in 2 hr = (3/20 + 2/15) = 17/60 ∴ Part of tank filled in 6 hr = (3*17/60) = 17/20 Remaining part = 1 - 17/20 = 3/20 Now it is the turn of A and B and 3/20 is filled by A and B in 1 hour. ∴ Total time taken to fill the tank = (6+1) = 7 hr