Calculate Power of X to N in C++

In this problem, we are given two integers x and n. Our task is to write a program to calculate the pow(x,n).

Let’s take an example to understand the problem,

Input

x = 5 , n = 3

Output

125

Program to calculate the pow(x,n),

Example

 Live Demo

#include <iostream>
using namespace std;
float myPow(float x, int y) {
   if(y == 0)
      return 1;
   float temp = myPow(x, y / 2);
   if (y % 2 == 0)
      return temp*temp;
   else {
      if(y > 0)
         return x*temp*temp;
      else
         return (temp*temp)/x;
   }
}
int main() {
   float x = 5;
   int n = 7;
   cout<<x<<" raised to the power "<<n<<" is "<<myPow(x, n);
   return 0;
}

Output

5 raised to the power 7 is 78125

The program shows an efficient approach by dividing the power into half and then multipling the two half and also considers the negative cases.