weixin_33712881 2017-10-16 09:08 采纳率: 0%
浏览 35

控制台日志JSON结果

I'm just starting to learn about APIs, JSON, and Jquery and I am stuck. How would I console log the following from my Jquery call -

name: "The Old Mill Cafe"

Here's my current code:

$(document).ready(function(){
  $("#mainbutton").on("click", function() {
    $.ajax({
      url: "https://developers.zomato.com/api/v2.1/search?entity_id=Chicago%2C%20IL%20&entity_type=city",
      headers: {
        "X-Zomato-API-Key": "…"
      },
      method: "GET"
    }).done(function(data) {
      console.log(data);
    });
  });
});
  • 写回答

2条回答 默认 最新

  • weixin_33691598 2017-10-16 09:12
    关注

    Your console.log is telling you that data is an object with a property called restaurants which is an array with a single entry. That entry is an object with a property called restaurant which is an object with a property called name. So:

    console.log(data.restaurants[0].restaurant.name);
    
    评论

报告相同问题?