========================================================================
MICROSOFT FOUNDATION CLASS LIBRARY : LCS
========================================================================
AppWizard has created this LCS application for you. This application
not only demonstrates the basics of using the Microsoft Foundation classes
but is also a starting point for writing your application.
This file contains a summary of what you will find in each of the files that
make up your LCS application.
LCS.dsp
This file (the project file) contains information at the project level and
is used to build a single project or subproject. Other users can share the
project (.dsp) file, but they should export the makefiles locally.
LCS.h
This is the main header file for the application. It includes other
project specific headers (including Resource.h) and declares the
CLCSApp application class.
LCS.cpp
This is the main application source file that contains the application
class CLCSApp.
LCS.rc
This is a listing of all of the Microsoft Windows resources that the
program uses. It includes the icons, bitmaps, and cursors that are stored
in the RES subdirectory. This file can be directly edited in Microsoft
Visual C++.
LCS.clw
This file contains information used by ClassWizard to edit existing
classes or add new classes. ClassWizard also uses this file to store
information needed to create and edit message maps and dialog data
maps and to create prototype member functions.
res\LCS.ico
This is an icon file, which is used as the application's icon. This
icon is included by the main resource file LCS.rc.
res\LCS.rc2
This file contains resources that are not edited by Microsoft
Visual C++. You should place all resources not editable by
the resource editor in this file.
/////////////////////////////////////////////////////////////////////////////
AppWizard creates one dialog class:
LCSDlg.h, LCSDlg.cpp - the dialog
These files contain your CLCSDlg class. This class defines
the behavior of your application's main dialog. The dialog's
template is in LCS.rc, which can be edited in Microsoft
Visual C++.
/////////////////////////////////////////////////////////////////////////////
Other standard files:
StdAfx.h, StdAfx.cpp
These files are used to build a precompiled header (PCH) file
named LCS.pch and a precompiled types file named StdAfx.obj.
Resource.h
This is the standard header file, which defines new resource IDs.
Microsoft Visual C++ reads and updates this file.
/////////////////////////////////////////////////////////////////////////////
Other notes:
AppWizard uses "TODO:" to indicate parts of the source code you
should add to or customize.
If your application uses MFC in a shared DLL, and your application is
in a language other than the operating system's current language, you
will need to copy the corresponding localized resources MFC42XXX.DLL
from the Microsoft Visual C++ CD-ROM onto the system or system32 directory,
and rename it to be MFCLOC.DLL. ("XXX" stands for the language abbreviation.
For example, MFC42DEU.DLL contains resources translated to German.) If you
don't do this, some of the UI elements of your application will remain in the
language of the operating system.
/////////////////////////////////////////////////////////////////////////////
VC++最长公共子序列

最长公共子序列(Longest Common Subsequence,LCS)是计算机科学中一种经典的字符串问题,主要应用于比较和分析两个或多个序列的相似性。在VC++环境下,我们可以使用C++编程语言来解决这个问题。本教程将详细介绍如何用VC++实现LCS算法,并提供相关的源代码供学习。
LCS问题的目标是找到两个序列中最长的子序列,这个子序列不必连续,但必须在原序列中都存在。例如,对于字符串"ABCDGH"和"ACDFGHR",它们的一个最长公共子序列是"ACDFG"。
在VC++中,我们可以采用动态规划(Dynamic Programming)方法来解决LCS问题。动态规划是一种通过将复杂问题分解成更小的子问题来求解的方法。对于LCS,我们可以构建一个二维数组dp,其中dp[i][j]表示字符串s1的前i个字符与字符串s2的前j个字符的LCS长度。
算法步骤如下:
1. 初始化:创建一个大小为m+1(m为第一个字符串长度)x n+1(n为第二个字符串长度)的二维数组dp,所有边界条件设为0,即dp[0][j]=0和dp[i][0]=0,表示空串与任何字符串的LCS长度为0。
2. 遍历:对于字符串s1的每个字符i,再遍历字符串s2的每个字符j,如果s1[i-1]等于s2[j-1],则dp[i][j] = dp[i-1][j-1] + 1,表示当前字符匹配,LCS长度增加1;否则,dp[i][j]取dp[i-1][j]和dp[i][j-1]中的较大值,表示不匹配时,取之前两者LCS的较大值。
3. 结果:最终,dp[m][n]就是两个字符串的LCS长度。如果需要获取具体的子序列,可以从dp数组的最后一行回溯。
在VC++中,你可以将上述逻辑封装到一个函数中,例如`int lcs(string s1, string s2)`,然后在主函数中调用此函数并打印结果。同时,可以使用递归或者栈记录回溯路径,以得到具体的LCS字符串。
以下是一个简单的VC++源代码示例,用于计算两个字符串的LCS:
```cpp
#include <iostream>
#include <string>
int lcs(const std::string &s1, const std::string &s2, int m, int n, int dp[][n + 1]) {
if (m == 0 || n == 0)
return 0;
if (s1[m - 1] == s2[n - 1])
return 1 + lcs(s1, s2, m - 1, n - 1, dp);
else
return std::max(lcs(s1, s2, m, n - 1, dp), lcs(s1, s2, m - 1, n, dp));
}
std::string getLCS(const std::string &s1, const std::string &s2) {
int m = s1.length(), n = s2.length();
int dp[m + 1][n + 1];
for (int i = 0; i <= m; i++) {
for (int j = 0; j <= n; j++) {
if (i == 0 || j == 0)
dp[i][j] = 0;
}
}
int len = lcs(s1, s2, m, n, dp);
std::string lcsStr;
while (len > 0) {
if (s1[m - 1] == s2[n - 1]) {
lcsStr += s1[m - 1];
m--;
n--;
} else if (dp[m][n - 1] >= dp[m - 1][n]) {
n--;
} else {
m--;
}
len--;
}
std::reverse(lcsStr.begin(), lcsStr.end());
return lcsStr;
}
int main() {
std::string str1 = "ABCDGH";
std::string str2 = "ACDFGHR";
std::cout << "最长公共子序列: " << getLCS(str1, str2) << std::endl;
return 0;
}
```
这段代码首先计算了两个字符串的LCS长度,然后回溯找到LCS并返回。运行上述代码,你会发现"ACDFG"是两个给定字符串的最长公共子序列。
学习这个例子,你可以深入了解动态规划的应用,以及如何在VC++环境中编写和调试C++代码。这将对你的编程技能和问题解决能力有所提升。

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