two-order-fun.rar_Fun_ Fun_ Fun

/* Note:Your choice is C IDE */ #include <stdio.h> #include <math.h> void main() { double a,b,c,delt,p1,p2,x1,x2,ix,ia,ib; printf("\n ○========☆自动解一元二次方程程序☆========○\n\n-------------------------------------------------------------------------------\n\n☆（温馨提示:输入各系数的值前请把一元二次方程转化为“axx+bx+c=0”的一般形式)\n\n●请输入方程各系数的值：\n\n"); printf("○请输入a的值:\n"); scanf("%lf",&a); printf("○请输入b的值:\n"); scanf("%lf",&b); printf("○请输入c的值:\n"); scanf("%lf",&c); delt=b*b-4*a*c; p1=(-b+sqrt(delt))/(2*a); p2=(-b-sqrt(delt))/(2*a); if(delt==0) { printf("\n结果描述：方程有两个相等的实数根\n"); x1=p1=x2=p2; printf(" \n☆结果：x1=x2=%8.1lf\n\n",p1,p2); printf("-----------------------------------------------------------------------＞＞＞＞"); } else if(delt>0) { x1=p1; x2=p2; printf("\n结果描述：方程有两个不相等的实数根\n"); printf("\n☆结果：x1=%8.1lf , x2=%8.1lf\n\n",p1,p2); printf("-----------------------------------------------------------------------＞＞＞＞"); } else if(delt<0) { ix=sqrt(-delt); ia=1/(2*a); ib=-b; // p1=ia*(-b+ix); // p2=ia*(-b-ix); printf("\n☆结果：方程虚解\n\n"); printf("\n☆结果： x1=%5.2lf*(%3.1lf+%3.1lf*i)\n\t x2=%5.2lf*(%3.1lf-%3.1lf*i)\n\n",ia,ib,ix,ia,ib,ix); printf("-----------------------------------------------------------------------＞＞＞＞"); } system("PAUSE"); }