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[zh] fix: minimum feasible nodes 50->100
Corresponds to #46994.
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content/zh-cn/docs/concepts/scheduling-eviction/scheduler-perf-tuning.md

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@@ -191,13 +191,13 @@ percentageOfNodesToScore: 50
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<!--
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`percentageOfNodesToScore` must be a value between 1 and 100 with the default
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value being calculated based on the cluster size. There is also a hardcoded
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minimum value of 50 nodes.
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minimum value of 100 nodes.
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-->
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`percentageOfNodesToScore` 的值必须在 1 到 100 之间,而且其默认值是通过集群的规模计算得来的。
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另外,还有一个 50 个 Node 的最小值是硬编码在程序中。
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另外,还有一个 100 个 Node 的最小值是硬编码在程序中。
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<!--
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{{< note >}} In clusters with less than 50 feasible nodes, the scheduler still
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{{< note >}} In clusters with less than 100 feasible nodes, the scheduler still
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checks all the nodes because there are not enough feasible nodes to stop
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the scheduler's search early.
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@@ -210,7 +210,7 @@ scheduler's performance significantly.
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{{< /note >}}
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-->
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{{< note >}}
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当集群中的可调度节点少于 50 个时,调度器仍然会去检查所有的 Node,
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当集群中的可调度节点少于 100 个时,调度器仍然会去检查所有的 Node,
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因为可调度节点太少,不足以停止调度器最初的过滤选择。
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同理,在小规模集群中,如果你将 `percentageOfNodesToScore`

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