#include <iostream> #include <vector> #include <string> #include <unordered_map> #include<algorithm> using namespace std; struct edge { int to, weight; edge(int t,int w):to(t),weight(w){} }; int main() { int n, m,sum=0,find=1,index=1; cin >> n >> m; vector<vector<edge>>graph(n + 1); vector<int>dist(n + 1, 10000000); vector<int>pre(n + 1, -1); for (int i = 1; i <= n; i++) { int a, b, c; cin >> a >> b >> c; sum += c; if (c) { graph[a].push_back(edge(b, c)); graph[b].push_back(edge(a, c)); if (find) { dist[a] = 0; index = a; find = 0; } } } int ans = 0; vector<int>visit(n + 1, 0); for (int i = 1; i <= n; i++) { int dmin = 10000000; int dex = -1; for (int j=1;j<=n;j++) { if (!visit[j] && dist[j] < dmin) { dmin = dist[j]; dex = j; } } if (dex == -1)continue; for (auto& it : graph[dex]) { if (!visit[it.to] && it.weight < dist[it.to]) { dist[it.to] = it.weight; pre[it.to] = dex; } } } for (int i = 1; i <= n; i++) { int b = pre[i]; if (b == -1 || dist[i] == 10000000)continue; for (auto& it : graph[i]) { if (it.to == b) { ans += it.weight; break; } } } cout << sum - ans;哪里错了 }

#include <iostream> #include<iomanip> using namespace std;九九乘法表

vc++2008编译不了#include头文件

### vc++2008 编译不了 #include<iostream.h> 头文件 #### 背景介绍在使用 Visual C++ 2008（以下简称 VC++ 2008）进行 C++ 编程时，可能会遇到无法编译包含 #include <iostream.h> 的代码的问题。这个问题主要...

#include <iostream>

#include <iostream> #include <iomanip> using namespace std; int main() { int n,i,k=0; cin>>n; for(i=n*n;i>=1;i--) { cout<<setw(5)<<i; k++; if(k%n==0) cout<<endl; } cout<<endl; return 0;

#include <iostream> #include <string> #include <map> #include <vector> #include <unordered_set> #include <algorithm> #include <chrono> #include <iomanip> #include <sstream> #include <ctime> // 跨平台头文件 #ifdef _WIN32 #include <conio.h> #else #include <termios.h> #include <unistd.h> #endif // ANSI颜色代码 #define COLOR_RESET "\033[0m" #define COLOR_RED "\033[31m" #define COLOR_GREEN "\033[32m" #define COLOR_YELLOW "\033[33m" #define COLOR_BLUE "\033[34m" #define COLOR_CYAN "\033[36m" using namespace std; // ---------------------- 全局定义 ---------------------- #define ADMIN "admin" enum UserType { NORMAL, ADMIN }; enum ActivityStatus { OPEN, CLOSED, EXPIRED }; // ---------------------- 数据结构 ---------------------- struct User { string username, password; UserType type = NORMAL; }; struct Comment { string username, content; time_t timestamp; unordered_set<string> commentLikes; int commentLikeCount = 0; }; struct Activity { int id

<think>好的，用户想了解C++的代码结构和定义，包括头文件、枚举、结构体和全局定义。首先，我需要整理这些部分的基本概念和用法，确保覆盖每个要点的核心内容。首先，头文件（Headers）在C++中非常重要，用于声明...

#include <iostream> #include <vector> #include <string> #include <unordered_map> #include<algorithm> using namespace std; struct edge { int to,wight; edge(int t, int w) :to(t), wight(w) {} }; vector<vector<edge>>graph; vector<int>visit(105, 0); vector>road; vector>current; int n, dmin = 10000000; void dfs(int k,int sum,int price) { if (sum == n) { if (dmin > price) { dmin = price; road.assign(current.begin(), current.end()); } return; } if (visit[k] == 1)return; visit[k] = 1; for (auto &it:graph[k]) { if (visit[it.to] == 0) { current.push_back({ k,it.to }); dfs(it.to, sum + 1, price + it.wight); current.pop_back(); } } visit[k] = 0; } int main() { int m; cin >> n >> m; graph.resize(n+1); for (int i = 0; i < m; i++) { int a, b, c; cin >> a >> b >> c; graph[a].push_back(edge(b, c)); graph[b].push_back(edge(a, c)); } dfs(1,1,0); for (auto& [a,b]:road) { cout << a << " " << b<<endl; } }为什么得不到正解

<think>嗯，我现在要分析一下用户提供的这段C++代码为什么不能得到正确的解。首先，我需要仔细阅读代码，理解它的功能，然后找出其中可能存在的错误或逻辑问题。首先，代码的大致结构是这样的：它定义了一个图的...

#include<iostream> #include<cstring> #include<vector> #include<unordered_map> #include<algorithm> #include<queue> #include<iomanip> #include<cmath> #include <fstream> #include <cstdlib> #include <map> // #define int long long using namespace std; const int N = 200010; int n,m,t,p; int ar[N],s[N],cnt,sum,ans; int dx[4]={0,0,1,-1},dy[4]={1,-1,0,0}; double a,b; string st; struct pe { double num,p; }pv[N]; bool cmp (pe a,pe b) { if(a.p==b.p)return a.num<b.num; return a.p>b.p; } void solve () { cin>>n; for(int i=0;i<n;i++) { cin>>a>>b; pv[i].p=a/(a+b); pv[i].num=i+1; } sort(pv,pv+n,cmp); for(int i=0;i<n;i++)cout<<pv[i].num<<" "; } int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); solve(); return 0; } 请找出代码错误

代码中没有明显的错误。但是，可能存在一些潜在的问题。 1. 在排序函数cmp中，当两个pe结构体的p值相等时，比较的是num值。这可能会导致不稳定的排序结果，如果对结果的顺序有要求，可能需要修改排序函数。...

#pragma once #include <iostream> #include <vector> #include <fstream> #include <algorithm> #include <unordered_map> using namespace std; class User_Gxy { public: string username_Gxy; string password_Gxy; User_Gxy(string _username, string _password) : username_Gxy(_username), password_Gxy(_password) {} }; class UserManager { private: vector<User_Gxy> users; string userFile; struct RatingRecord { int movieId; string movieName; float rating; RatingRecord(int _movieId, string _movieName, float _rating) : movieId(_movieId), movieName(_movieName), rating(_rating) {} }; unordered_map<string, vector<RatingRecord>> ratingRecords; public: UserManager(string _userFile) : userFile(_userFile) {} void loadUsers_Gxy(); void saveUsers_Gxy(); void registerUser_Gxy(string username, string password); bool loginUser_Gxy(string username, string password); void addRatingRecord_Gxy(string username, int movieId, string movieName, float rating); void viewRatingRecords_Gxy(string username); void rateMovie_Gxy(string username, int movieId, string movieName, float musicRating, float visualRating, float storyRating, float performanceRating); }; 代码解释

这段代码是一个用户管理和评分记录系统，其中包含两个类：User_Gxy和UserManager。 ...构造函数用于初始化这些属性。 UserManager类用于管理用户和评分记录，包含一个私有的users向量、一个userFile字符串和一个...

优化这段代码#include <iostream> #include <iomanip> #include <stdio.h> #include <fstream> #include <string> #include <algorithm> #include <unordered_map> #include <map> #include <stack> #include <set> #include <vector> using namespace std; struct Production { char left; // 产生式的左部非终结符 string right; // 产生式的右部字符串 }; map<char, set<char>> firstSets; int main() { vector productions; ifstream infile("grammar.txt"); char left; string right; while (infile >> left >> right) { productions.push_back({ left, right }); } for (auto p : productions) { char left = p.left; string right = p.right; char firstChar = right[0]; if (isupper(firstChar)) { // 如果是非终结符 // 计算非终结符的first集合 set<char> firstSet = firstSets[firstChar]; for (int i = 0; i < right.length(); i++) { char ch = right[i]; if (isupper(ch)) { // 如果是非终结符 firstSet.insert(firstSets[ch].begin(), firstSets[ch].end()); if (firstSets[ch].find('$') == firstSets[ch].end()) { // 如果该非终结符没有空串 break; } } else { // 如果是终结符 firstSet.insert(ch); break; } } firstSets[left].insert(firstSet.begin(), firstSet.end()); } else { // 如果是终结符 firstSets[left].insert(firstChar); } } for (auto p : productions) { char left = p.left; cout << "First(" << left << ") = {"; for (auto ch : firstSets[left]) { cout << ch << ", "; } cout << "}" << endl; } }使得能正确求出frist集

set<char> calcFirstSet(char ch, const vector<Production>& productions, map<char, set<char>>& firstSets) { // 如果该字符已经计算过first集合，直接返回 if (firstSets.find(ch) != firstSets.end()) { ...

#include <iostream> #include <vector> #include <unordered_map> #include <queue> #include <algorithm> using namespace std; struct WordFreq { string word; int freq; bool operator<(const WordFreq& other) const { return freq == other.freq ? word > other.word : freq < other.freq; } }; vector<string> topKFrequent(vector<string>& words, int k) { unordered_map<string, int> freq; for (const auto& word : words) { freq[word]++; } priority_queue<WordFreq, vector<WordFreq>> pq; for (const auto& [word, f] : freq) { pq.push({word, f}); if (pq.size() > k) { pq.pop(); } } vector<string> result(k); for (int i = k - 1; i >= 0; i--) { result[i] = pq.top().word; pq.pop(); } return result; } int main() { int k; cin >> k; vector<string> words; string word; while (cin >> word) { if (word == "end") { break; } words.push_back(word); } auto result = topKFrequent(words, k); for (const auto& word : result) { cout << word << " "; } cout << endl; return 0; }

#include <unordered_map> #include <queue> #include <algorithm> using namespace std; // 定义一个结构体，用于存储单词和对应的频率 struct WordFreq { string word; int freq; bool operator<(const ...

#include <iostream> #include <vector> #include <string> #include <unordered_map> #include<algorithm> #include<tuple> #include<queue> using namespace std; class UnionFind { private: int find(int x) { if (parent[x] != x)parent[x] = find(parent[x]); return parent[x]; } public: vector<int>parent; UnionFind(int size) { parent.resize(size + 1); for (int i = 0; i <= size; i++)parent[i] = i; } void unite(int x, int y) { int rootx = find(x); int rooty = find(y); parent[rooty] = rootx; } int ancester(int x) { return find(x); } }; int main() { int n, m,money=0; cin >> n >> m; UnionFind p(n); priority_queue<tuple<int, int, int>, vector<tuple<int, int, int>>, greater<tuple<int, int, int>>>heap; vector<int>dist(n + 1,10000000); while (m--) { int a, b, c, d; cin >> a >> b >> c >> d; if (a == 1) { p.unite(b, c); money += d; } else { heap.push({ d,c,b }); } } while (heap.empty()) { auto [dist, a, b] = heap.top(); heap.pop(); if (p.ancester(a) == p.ancester(b))continue; p.unite(a, b); money += dist; } cout << money; }哪里有问题

<think>好的，我现在需要帮用户分析他的代码有什么问题。首先，用户提供的代码是一个使用并查集（UnionFind）和最小堆（priority_queue）来处理两种类型操作的程序。看起来像是某种图算法，可能是在处理最小生成树的...

优化finding函数，#include<algorithm> #include<iostream> #include<vector> #include<string> #include<cmath> #include <cstdio> #include <map> #include <unordered_map> #include <queue> using namespace std; const int INF = 0x3f3f3f3f; int n, gamma, time_count=0; int time[10]; string alpha; vector<int> Length(50005, 0); unordered_map<string, int> number; unordered_map<int, string> nega_number; vector<unordered_map<int, int>> edge(50005); vector<int> trace(50005, 0); vector<int> final_trace; void finding(string alpha) { int a=number[alpha], b; char beta; string epsilon; for(int i=9; i>=0; i--) { for(int j=1; j<10; j++) { epsilon = alpha; epsilon[i] = '0' + (int(epsilon[i]) + j) % 10; if(number.find(epsilon) != number.end() and epsilon != alpha) { b = number[epsilon]; edge[a][b]= time[i]; } } for(int j=i-1; j>=0; j--) { epsilon = alpha; beta = epsilon[j]; epsilon[j] = epsilon[i]; epsilon[i] = beta; if(number.find(epsilon) != number.end() and epsilon != alpha) { b = number[epsilon]; edge[a][b]= time[j]; } } } } void dijkstra(int i) { priority_queue, vector>, greater>> q; vector<bool> vis(n+1, false); q.push({0, i}); Length[i] = 0; while(!q.empty()) { int u = q.top().second; q.pop(); if(vis[u]) continue; vis[u] = true; for(auto j : edge[u]) { int v = j.first, w = j.second; if(Length[v] > Length[u] + w) { Length[v] = Length[u] + w; trace[v] = u; q.push({Length[v], v}); } } } } int main() { cin>>n; for(int i=2; i<n+1;i++) { Length[i] = INF; } for(int i=0; i<10; i++) { cin>>time[i]; } for(int i=0; i<n; i++) { cin>>alpha; nega_number[i] = alpha; number[alpha] = i+1; } for(int i=0; i<n; i++) { alpha = nega_number[i]; finding(alpha); } dijkstra(1); if(Length[n] == INF) { cout<<"-1"; } else { gamma = n; final_trace.push_back(gamma); cout<<Length[n]<<endl; while(gamma != 1) { gamma = trace[gamma]; final_trace.push_back(gamma); } cout<<final_trace.size()<<endl; for(int i=final_trace.size()-1;i>-1;i--) { cout<<final_trace[i]<<" "; } } system("pause"); return 0; }

1. 将string类型的alpha改为int类型的a，避免在函数中多次进行string和int类型的转换。 2. 将时间复杂度较高的除法运算改为直接进行取余运算。优化后的代码如下： c++ void finding(int a) { int b; string...

#include<algorithm> #include<iostream> #include<vector> #include<string> #include<cmath> #include <cstdio> #include <map> #include <unordered_map> using namespace std; const int INF = 0x3f3f3f3f; int n, gamma, time_count=0; int time[10]; string alpha; vector<int> Length(50005, 0); unordered_map<string, int> number; unordered_map<int, string> nega_number; vector<unordered_map<int, int>> edge(50005); vector<int> trace(50005, 0); vector<int> final_trace; void finding(string alpha) { int a=number[alpha], b; char beta; string epsilon; for(int i=9; i>=0; i--) { for(int j=1; j<10; j++) { epsilon = alpha; epsilon[i] = '0' + (int(epsilon[i]) + j) % 10; if(number.find(epsilon) != number.end() and epsilon != alpha) { b = number[epsilon]; edge[a][b]= time[i]; } } for(int j=i-1; j>=0; j--) { epsilon = alpha; beta = epsilon[j]; epsilon[j] = epsilon[i]; epsilon[i] = beta; if(number.find(epsilon) != number.end() and epsilon != alpha) { b = number[epsilon]; edge[a][b]= time[j]; } } } } void dijkstra(int i) { int beta; for(auto j : edge[i]) { beta = Length[j.first]; if(beta > Length[i] + j.second) { Length[j.first] = Length[i] + j.second; trace[j.first] = i; if(beta == INF) { dijkstra(j.first); } } } } int main() { cin>>n; for(int i=2; i<n+1;i++) { Length[i] = INF; } for(int i=0; i<10; i++) { cin>>time[i]; } for(int i=0; i<n; i++) { cin>>alpha; nega_number[i] = alpha; number[alpha] = i+1; } for(int i=0; i<n; i++) { alpha = nega_number[i]; finding(alpha); } dijkstra(1); if(Length[n] == INF) { cout<<"-1"; } else { gamma = n; final_trace.push_back(gamma); cout<<Length[n]<<endl; while(gamma != 1) { gamma = trace[gamma]; final_trace.push_back(gamma); } cout<<final_trace.size()<<endl; for(int i=final_trace.size()-1;i>-1;i--) { cout<<final_trace[i]<<" "; } } //system("pause"); return 0; }修改当中的dijkstra

priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> q; vector<bool> vis(n+1, false); q.push({0, i}); Length[i] = 0; while(!q.empty()) { int u = q.top().second; q....

#include <iostream> #include <vector> #include <string> #include <unordered_map> #include<algorithm> #include<tuple> #include<queue> using namespace std; class UnionFind { private: int find(int x) { if (parent[x] != x)parent[x] = find(parent[x]); return parent[x]; } public: vector<int>parent; UnionFind(int size) { parent.resize(size + 1); for (int i = 0; i <= size; i++)parent[i] = i; } void unite(int x, int y) { int rootx = find(x); int rooty = find(y); if (rootx > rooty) parent[rooty] = rootx; else parent[rootx] = rooty; } int ancester(int x) { return find(x); } }; struct pair_hash { template<class t1,class t2> size_t operator()(const pair<t1, t2>& p)const { auto h1 = hash<t1>{}(p.first); auto h2 = hash<t2>{}(p.second); return h1 ^ h2; } }; int main() { int m, n,t=1,price=0; cin >> m >> n; unordered_map, int,pair_hash>rtu; for (int i = 1; i <= m; i++) { for (int j = 1; j <= n; j++) { rtu[{i,j}] = t++; } } UnionFind p(n * m); int a, b, c, d; while (cin >> a >> b >> c >> d) { p.unite(rtu[{a,b}], rtu[{c,d}]); } for (int i = 1; i <= n; i++) { for (int j = 1; j < m; j++) { if (p.ancester(rtu[{j, i}]) != p.ancester(rtu[{j + 1, i}])) { p.unite(rtu[{j, i}], rtu[{j + 1, i}]); price += 1; } } } for (int i = 1; i < n; i++) { if (p.ancester(rtu[{1,i}]) != p.ancester(rtu[{1,i+1}])) price += 2; } cout << price; }该代码运行效率很低吗为什么会超时

using namespace std; class UnionFind { private: vector<int> parent, rank; int find(int x) { return parent[x] == x ? x : parent[x] = find(parent[x]); } public: UnionFind(int size) : parent(size+1...

优化改进以下代码#include <iostream> #include <fstream> #include <string> #include <vector> #include <algorithm> #include <iterator> using namespace std; typedef istream_iterator<string> string_input; void welcome() { cout << "* 变位词查找系统***\n" << "在词典中找出给定的字符串的所有变位词" << endl; } void readDict(vector<string> & dictionary) { cout << "首先，请输入词典的文件名称：" << endl; string dictionary_name; cin >> dictionary_name; ifstream ifs(dictionary_name.c_str()); if (!ifs.is_open()) { cerr << "异常：文件"<< dictionary_name << "没有找到 " << endl; exit(1); } cout << "词典读入中 ..." << flush; copy(string_input(ifs), string_input(), back_inserter(dictionary)); sort(dictionary.begin(),dictionary.end()); cout << "词典包含有 " << dictionary.size() << " 个单词\n\n"; ifs.close(); } void analyseAnagram(const vector<string> & dictionary) { cout << "请输入单词（或任意字母序列）" << endl; for (string_input p(cin); p != string_input(); ++p) { cout << "查找输入单词的变位词中..." << endl; string word = *p; sort(word.begin(), word.end()); bool found_one = false; do { if (binary_search(dictionary.begin(), dictionary.end(), word)) { cout << " " << word ; found_one = true; } } while (next_permutation(word.begin(), word.end())); if (!found_one) cout << " 抱歉，没有找到变位词\n"; cout << "\n请输入下一个单词 " << "(或输入Ctrl+Z终止程序 ) \n" << endl; } } int main() { welcome(); vector<string> dictionary; readDict(dictionary); analyseAnagram(dictionary); system("pause"); return 0; }

unordered_set<string> dict_set(dictionary.begin(), dictionary.end()); ... if (dict_set.count(word)) 3. 在查找变位词时，可以使用一个 map 来记录每个单词的字母出现次数，避免使用 next_permutation ...

#include<iostream> #include<string> #include<vector> #include<unordered_map> #include<algorithm> using namespace std; int main() { int n, m, k; cin >> n >> m >> k; vector>qq; while (n--) { long long a; cin >> a; string b; cin >> b; qq.push_back(make_pair(a,b)); } while (m--) { vector>ww; unordered_map<string,int>nus; string a; cin >> a; for (int i = 0; i < qq.size(); i++) { for (int j = 0; j < a.size(); j++) { if (qq[i].second.size()<a.size()||a[j] != qq[i].second[j]) break; if (j ==a.size()-1&&a.size()!=qq[i].second.size()) ww.push_back(qq[i]); } } if (ww.empty()) cout << "no suggestion"<<endl; else { sort(ww.begin(), ww.end(), [](const pair<long long, string>& a, const pair<long long, string>& b) { if (a.first != b.first) { return a.first > b.first; } else { return a.second < b.second; } }); int i = 0; while (i < ww.size() && i < k) { if (nus.find(ww[i].second)==nus.end()) { nus[ww[i].second] = 1; cout << ww[i].second << endl; } i++; } } if(m!=0) cout << endl; } }帮我纠错

首先，用户提供的代码开头是#include iostream string vector unordered_map algorithm，看起来像是想包含多个头文件，但C++中每个头文件都需要单独使用#include指令，并且用尖括号或引号括起来。这里用户可能漏...

#include <iostream> #include <vector> #include <algorithm> #include <sstream> using namespace std; bool isValidSet(int a, int b, int c) { return (a == b && b == c) || (a + 1 == b && b + 1 == c); } string checkHu(vector<int>& nums) { int n = nums.size(); if (n % 3 != 2) { return "XIANGGONG"; } sort(nums.begin(), nums.end()); for (int i = 0; i < n - 5; i += 3) { if (!isValidSet(nums[i], nums[i + 1], nums[i + 2])) { return "BUHU"; } } if (nums[n - 2] != nums[n - 1]) { return "BUHU"; } return "HU"; } int main() { vector<int> nums; string line; string result; while (true) { getline(cin, line); if (line == "0") { break; } stringstream ss(line); int num; while (ss >> num) { nums.push_back(num); } result = checkHu(nums); cout << result << endl; nums.clear(); } return 0; }如何加以定义个数字的数量不超过4个，集合中元素的数量不超过14个

#include <unordered_map> // 添加头文件以使用 unordered_map using namespace std; bool isValidSet(int a, int b, int c) { return (a == b && b == c) || (a + 1 == b && b + 1 == c); } string checkHu...

帮我优化时间复杂度：#include<iostream> #include<algorithm> #include<string> #include<unordered_map> using namespace std; int main() { unordered_map<string, string>curses; string curse; while ((getline(cin, curse)) && (curse != "END")) { size_t pos = curse.find(']'); string name = curse.substr(1, pos - 1); string effect = curse.substr(pos + 2);//因为']'后面有一个空格 curses[name] = effect; } int N; cin >> N; getchar();//很重要，读取上一个换行符 for (int i = 0; i < N; i++) { string query; getline(cin, query); if (query[0]=='[') //输入的是诅咒名字 { size_t cinPos = query.find(']'); string cinNmae = query.substr(1, cinPos - 1); if (curses.count(cinNmae)) cout << curses[cinNmae] << endl; else cout << "silence" << endl; } else //输入的是诅咒效果 { bool flag = 0; for (auto it = curses.begin(); it != curses.end(); it++) { if (query.compare(it->second) == 0) { cout << it->first << endl; flag = 1; break; } } if(flag==0) cout << "silence" << endl; } } return 0; }

为了优化时间复杂度，我们可以考虑使用一个 unordered_map<string, vector<string>>，其中 vector 中存储的是具有相同诅咒效果的诅咒名称。这样，查询操作的时间复杂度就可以降为 $O(1)$，具体实现如下： ...

#include <iostream> #include <vector> #include <string> #include <random> #include <algorithm> using namespace std; vector<string> generate_sequences(int n) { vector<string> sequences; const char bases[] = { ‘A’, ‘T’, ‘C’, ‘G’ }; random_device rd; mt19937 gen(rd()); uniform_int_distribution<> dis(0, 3); for (int i = 0; i < n; ++i) { string s; s.reserve(60); for (int j = 0; j < 60; ++j) { s += bases[dis(gen)]; } sequences.push_back(s); } return sequences; } string find_common_substring(const vector<string>& sequences) { if (sequences.empty() || sequences[0].length() < 3) return “no significant commonalities”; const string& first = sequences[0]; int max_len = first.length(); for (int L = max_len; L >= 3; --L) { for (int i = 0; i <= first.length() - L; ++i) { string candidate = first.substr(i, L); bool all_contain = all_of( sequences.begin(), sequences.end(), [&candidate](const string& s) { return s.find(candidate) != string::npos; } ); if (all_contain) return candidate; } } return "no significant commonalities"; } int main() { int m, n; cout << "输入序列组数m: "; cin >> m; for (int i = 0; i < m; i++) { cout << endl; cout << "输入序列数量n: "; cin >> n; auto sequences = generate_sequences(n); cout << "\n生成的DNA序列:\n"; for (const auto& s : sequences) { cout << s << endl; } string result = find_common_substring(sequences); cout << "\n检测结果: " << result << endl; } return 0; } 将这个程序的匹配算法进行优化

在find_common_substring函数中，首先预处理所有其他序列的子串，存入一个vector<unordered_set<string>>，每个元素对应一个序列的所有可能子串。然后，对于第一个序列的每个候选子串，检查是否每个其他序列的集合...

#include <iostream> #include <vector> #include <algorithm> #include <sstream>使用命名空间 std;bool isValidSet（int a， int b， int c） { return （a == b && b == c） ||（a + 1 == b && b + 1 == c）;} string checkHu（vector<int>& nums） { int n = nums.size（）; if （n % 3 ！= 2） { return “xianggong”; } sort（nums.begin（）， nums.end（））; for （int i = 0; i < n - 5; i += 3） { if （！isValidSet（nums[i]， nums[i + 1]， nums[i + 2]）） { return “BUHU”; } } if （nums[n - 2] ！= nums[n - 1]） { return “BUHU”; } return “HU”; } int main（） { vector<int> nums; string line; string result; while （true） { getline（cin，行）;if （line == “0”） { break; } stringstream ss（line）;整数;while （ss >> num） { nums.push_back（num）; } result = checkHu（nums）;cout <<结果<< endl;nums.clear（）;} 返回 0;}如何加以定义个数字的数量不超过4个，集合中元素的数量不超过14个不用返回不胡

#include <unordered_map> using namespace std; bool isValidSet(int a, int b, int c) { return (a == b && b == c) || (a + 1 == b && b + 1 == c); } void checkHu(vector<int>& nums) { // 修改返回值类型...

#include <algorithm> #include <deque> #include <iostream> #include <unordered_set> #include <vector> using namespace std; int main() { int n; cin >> n; vector<int> zu(n + 1), zu1(n + 1); zu[0] = 0; zu1[0] = 0; for (int i = 1; i <= n; ++i) { cin >> zu[i]; zu1[i] = zu[i]; } sort(zu1.begin(), zu1.end()); int max_value = zu1[n]; vector<int> pos(max_value + 1, 0); // 初始化为0 vector<bool> tf(max_value + 1, false); // 使用vector<bool>代替C风格数组 unordered_set<int> in_queue; // 用于快速查找元素是否在队列中 int t; cin >> t; deque<int> dq; for (int i = 0; i < t; ++i) { string op; cin >> op; if (op[0] == 'D') { // Dequeue操作 if (dq.empty()) { cout << -1 << endl; } else { cout << dq.front() << endl; int front_value = zu[dq.front()]; tf[front_value] = dq.size() > 1 && front_value == zu[dq[1]]; pos[front_value]--; in_queue.erase(dq.front()); dq.pop_front(); } } else { // Enqueue操作 int z; cin >> z; int z_value = zu[z]; if (tf[z_value]) { // 如果优先级已存在，尝试插入队列中 if (in_queue.find(z) == in_queue.end()) { auto it = dq.begin(); while (it != dq.end() && zu[*it] != z_value) { ++it; } dq.insert(it, z); pos[z_value]++; } } else { // 如果优先级不存在，直接插入队尾 dq.push_back(z); tf[z_value] = true; pos[z_value] = dq.size(); in_queue.insert(z); } } } return 0; }优化使运行更快

例如，用unordered_map<int, pair<deque<int>::iterator, deque<int>::iterator>>来记录每个优先级组的起始和结束位置。但这样维护起来可能复杂，因为deque的迭代器在插入或删除后可能失效。或者，可以考虑将队列...

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