用C语言解决问题：1.创建图(邻接矩阵和邻接表两种方法) 2.图的深度和广度优先搜索结果 3.判断图是否为连通图，并打印其连通分量 4.判断图中是否存在顶点Vi到顶点Vj的简单路径 并输出该路径上的顶点 5.打印图中各顶点的度。

好的,我来为您解答如何使用C语言解决这些问题: 1. 创建图(邻接矩阵和邻接表两种方法): 邻接矩阵: ```c #define MAX_VERTEX_NUM 100 typedef struct { int vexs[MAX_VERTEX_NUM]; int arcs[MAX_VERTEX_NUM][MAX_VERTEX_NUM]; int vexnum, arcnum; } MGraph; ``` 邻接表: ```c #define MAX_VERTEX_NUM 100 typedef struct ArcNode { int adjvex; struct ArcNode *next; } ArcNode; typedef struct VNode { int data; ArcNode *first; } VNode, AdjList[MAX_VERTEX_NUM]; typedef struct { AdjList vertices; int vexnum, arcnum; } ALGraph; ``` 2. 图的深度优先搜索(DFS)和广度优先搜索(BFS): DFS: ```c void DFS(Graph G, int v, int visited[]) { printf("%d ", v); visited[v] = 1; for (int i = 0; i < G.vexnum; i++) { if (G.arcs[v][i] && !visited[i]) { DFS(G, i, visited); } } } ``` BFS: ```c void BFS(Graph G, int v, int visited[]) { int queue[MAX_VERTEX_NUM], front = 0, rear = 0; printf("%d ", v); visited[v] = 1; queue[rear++] = v; while (front < rear) { int u = queue[front++]; for (int i = 0; i < G.vexnum; i++) { if (G.arcs[u][i] && !visited[i]) { printf("%d ", i); visited[i] = 1; queue[rear++] = i; } } } } ``` 3. 判断图是否为连通图，并打印其连通分量: ```c void ConnectedComponents(Graph G) { int visited[MAX_VERTEX_NUM] = {0}; for (int i = 0; i < G.vexnum; i++) { if (!visited[i]) { printf("Component %d: ", i); DFS(G, i, visited); printf("\n"); } } } ``` 4. 判断图中是否存在顶点Vi到顶点Vj的简单路径，并输出该路径上的顶点: ```c int found = 0; void FindPath(Graph G, int vi, int vj, int path[], int len) { path[len] = vi; visited[vi] = 1; if (vi == vj) { found = 1; for (int i = 0; i <= len; i++) { printf("%d ", path[i]); } printf("\n"); } else { for (int i = 0; i < G.vexnum; i++) { if (G.arcs[vi][i] && !visited[i]) { FindPath(G, i, vj, path, len + 1); } } } visited[vi] = 0; } ``` 5. 打印图中各顶点的度: ```c void PrintDegrees(Graph G) { for (int i = 0; i < G.vexnum; i++) { int degree = 0; for (int j = 0; j < G.vexnum; j++) { if (G.arcs[i][j]) degree++; } printf("Vertex %d: degree %d\n", i, degree); } } ``` 这些代码片段提供了基本的实现框架，您可能需要根据具体的图结构和需求进行调整和完善。