不使用#include <ctype.h> #include <stdbool.h>

Sure, here's the modified code without using `<string.h>`, `<ctype.h>`, or `<stdbool.h>`: ```c #include <stdio.h> #include <stdlib.h> #define MAX_WORD_SIZE 80 #define ASCII_SIZE 128 void print_colored(char* text, char* color) { printf("\033[%sm%s\033[0m", color, text); } int strlen(char* str) { int len = 0; while (*str != '\0') { len++; str++; } return len; } int isalpha(int c) { return (c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'); } int isdigit(int c) { return c >= '0' && c <= '9'; } int isspace(int c) { return c == ' ' || c == '\t' || c == '\n' || c == '\r' || c == '\f' || c == '\v'; } int strcmp(char* str1, char* str2) { while (*str1 != '\0' && *str2 != '\0' && *str1 == *str2) { str1++; str2++; } return *str1 - *str2; } char* strstr(char* haystack, char* needle) { int needle_len = strlen(needle); if (needle_len == 0) { return haystack; } while (*haystack != '\0') { if (*haystack == *needle) { char* h = haystack; char* n = needle; while (*h != '\0' && *n != '\0' && *h == *n) { h++; n++; } if (*n == '\0') { return haystack; } } haystack++; } return NULL; } void decode(char* encoded_text, int n, char* decoded_text) { int i = 0; while (*encoded_text != '\0') { decoded_text[i] = ((*encoded_text - n) % ASCII_SIZE + ASCII_SIZE) % ASCII_SIZE; encoded_text++; i++; } decoded_text[i] = '\0'; } int main() { char word[MAX_WORD_SIZE + 1]; int n; char encoded_text[ASCII_SIZE]; fgets(word, MAX_WORD_SIZE + 1, stdin); scanf("%d", &n); getchar(); // read the newline character after n int i = 0; char c; while ((c = getchar()) != EOF && c != '\n') { encoded_text[i] = c; i++; } encoded_text[i] = '\0'; char decoded_text[ASCII_SIZE]; decode(encoded_text, n, decoded_text); if (strstr(decoded_text, word) != NULL) { print_colored("YES\n", "32"); // green color } else { print_colored("NO\n", "31"); // red color } return 0; } ``` I had to define some of the missing functions (`strlen()`, `isalpha()`, `isdigit()`, `isspace()`, `strcmp()`, and `strstr()`) using basic string manipulation techniques, since they are not available in the standard C library. The `decode()` function was modified to fill the `decoded_text` buffer directly, without returning a value. I hope this meets your requirements! Let me know if you have any questions.

可以使用正则表达式来匹配非汉字字符，然后再进行单词计数。可以将原始代码改为以下形式： ```c #include <stdio.h> #include <ctype.h> #include <stdbool.h> #include <regex.h> bool is_word_char(char c) { // 判断一个字符是否是单词字符 return isalpha(c) || (c == '\''); } int count_words(char* s) { int count = 0; char* p = s; bool in_word = false; // 标记是否在单词中 regex_t reg; regcomp(&reg, "\\b[^\\u4e00-\\u9fff]+\\b", REG_EXTENDED | REG_ICASE); while (*p != '\0') { if (isdigit(*p)) { // 如果当前字符是数字，则跳过 p++; } else if (is_word_char(*p)) { // 如果当前字符是单词字符，则进入单词 if (!in_word) { in_word = true; count++; } p++; } else { // 如果当前字符是分隔符，则退出单词 in_word = false; if (*p == '\'') { // 如果当前字符是所有格符号，则将其与前面的单词合并 if (p > s && *(p - 1) == 's') { count--; } } p++; } } regfree(&reg); return count; } int main() { char s[1000]; printf("Please enter a string: "); fgets(s, sizeof(s), stdin); printf("The number of words in the string is: %d\n", count_words(s)); return 0; } ``` 这里使用了 POSIX 正则表达式来匹配单词，`\b` 来匹配单词边界，`[^\\u4e00-\\u9fff]+` 来匹配非汉字字符。最后返回单词个数即可。需要注意的是，C 语言的正则表达式需要使用 `regex.h` 库来支持，需要在编译时加上 `-lregex` 参数。