stm32串口dma接收不定长hal库
时间: 2025-05-27 14:12:33 浏览: 26
### STM32 HAL库实现串口DMA不定长接收
为了处理STM32上通过HAL库使用DMA进行不定长的数据接收,可以采用串口空闲中断加DMA接收机制。这种方式能够有效解决数据长度未知的问题,在接收到一段完整的数据之后再做相应处理[^2]。
下面是一个简单的例子来展示如何配置并启动这种模式下的UART通信:
#### 初始化设置
首先定义全局变量用于存储接收到的数据以及记录当前已接收的数据量:
```c
#define BUFFER_SIZE 100 // 缓冲区大小可根据实际需求调整
uint8_t rx_buffer[BUFFER_SIZE];
volatile uint16_t received_length = 0;
```
接着初始化UART外设及其对应的DMA通道,并开启IDLE线状态检测功能以便于识别消息结束位置:
```c
static void MX_USART2_UART_Init(void)
{
huart2.Instance = USART2;
huart2.Init.BaudRate = 115200;
huart2.Init.WordLength = UART_WORDLENGTH_8B;
huart2.Init.StopBits = UART_STOPBITS_1;
huart2.Init.Parity = UART_PARITY_NONE;
huart2.Init.Mode = UART_MODE_TX_RX;
huart2.Init.HwFlowCtl = UART_HWCONTROL_NONE;
huart2.Init.OverSampling = UART_OVERSAMPLING_16;
if (HAL_UART_Init(&huart2) != HAL_OK)
{
Error_Handler();
}
/* Enable the UART Data Register not empty Interrupt */
__HAL_UART_ENABLE_IT(&huart2, UART_IT_IDLE);
}
```
最后注册回调函数以响应特定事件的发生,比如当发生空闲线条件时即表示一帧新的数据已经全部到达,则停止DMA传输并将接收到的内容传递给应用程序层进一步解析;同时重置计数器准备下一轮读取操作:
```c
void HAL_UART_RxCpltCallback(UART_HandleTypeDef *UartHandle)
{
if (UartHandle->Instance == USART2){
received_length += UartHandle->RxXferSize - __HAL_DMA_GET_COUNTER(UartHandle->hdmarx);
// Process data here or store it somewhere safe
// Restart DMA reception after processing current buffer content
HAL_UART_Receive_DMA(&huart2,rx_buffer,BUFFER_SIZE);
// Reset counter for next frame detection
__HAL_UART_CLEAR_IDLEFLAG(&huart2);
}
}
// This function will be called when IDLE line detected.
void HAL_UART_ErrorCallback(UART_HandleTypeDef *UartHandle)
{
if (__HAL_UART_GET_FLAG(UartHandle, UART_FLAG_IDLE)){
// Handle any error conditions that may have occurred during transmission/reception
// For example clear errors and restart receiving process as needed.
// Restart DMA reception immediately to catch new incoming frames without delay
HAL_UART_Receive_DMA(&huart2,rx_buffer,BUFFER_SIZE);
}
}
```
上述代码片段展示了基于STM32 HAL库构建的一个基本框架,允许设备持续监听来自外部源的消息直到遇到空闲间隔为止。需要注意的是,具体应用场合可能还需要额外考虑诸如超时保护等因素以增强系统的健壮性和可靠性[^1]。
阅读全文
相关推荐













