首页unsigned int x=134; unsigned int y=246; int m=x; int n=y; unsigned int z1=x-y; unsigned int z2=x+y; int k1=m-n; int k2=m+n;

unsigned int x=134; unsigned int y=246; int m=x; int n=y; unsigned int z1=x-y; unsigned int z2=x+y; int k1=m-n; int k2=m+n;

时间: 2023-12-03 20:04:28 浏览: 162

The code you have written is not correct syntax in any programming language. There are two errors: 1. The operator for multiplication is missing between x and y in the line `z2=x y;`. It should be `z2=x*y;`. 2. The operators for subtraction and multiplication are not defined for unsigned integers in the lines `z1=x-y;` and `z2=x*y;`. The result could potentially be negative or too large to store in an unsigned integer. Here is corrected code with proper syntax and type conversions to prevent errors: ``` unsigned int x=134; unsigned int y=246; int m=x; int n=y; int k1=m-n; int k2=m*n; int z1; unsigned int z2; if (x >= y) { z1 = x - y; z2 = x * y; } else { z1 = y - x; z2 = y * x; } ``` Note that I changed the type of `z1` to `int` to allow for negative results, and added an if statement to handle the case where `y` is larger than `x`. Also, the types of `k1` and `k2` were changed to `int` to match the result of subtracting and multiplying `int` values.

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