分支限界法求n皇后问题效果图
时间: 2024-12-30 22:17:47 浏览: 50
### 使用分支限界法求解N皇后问题的可视化
在探讨如何通过分支限界法(branch and bound)来解决N皇后问题并实现其可视化效果时,可以借助图形化界面展示算法执行过程中的状态变化。此方法能够有效地帮助理解该类组合优化问题的求解机制。
#### 构建基本框架
为了创建一个简单的可视化工具,Python编程语言及其库matplotlib和pygame是非常合适的选择。下面是一个简化版的例子:
```python
import numpy as np
import matplotlib.pyplot as plt
from time import sleep
def draw_board(board):
"""绘制棋盘"""
fig, ax = plt.subplots()
n = board.shape[0]
ax.imshow(-board, cmap='binary')
for i in range(n + 1):
ax.axhline(y=i - .5, color='.7', lw=2)
ax.axvline(x=i - .5, color='.7', lw=2)
plt.xticks([])
plt.yticks([])
def branch_and_bound_n_queens(N, delay=.5):
solutions = []
col_free = [True] * N
up_free = [True] * (2*N - 1)
down_free = [True] * (2*N - 1)
queens = {}
row_Qs = []
def placequeen(row_num):
global solution_count
for col_index in range(N):
if col_free[col_index] and \
up_free[row_num + col_index] and \
down_free[N - 1 + col_index - row_num]:
queens[row_num] = col_index
col_free[col_index] = False
up_free[row_num + col_index] = False
down_free[N - 1 + col_index - row_num] = False
if row_num == N-1:
sol = ['.'*i+'Q'+'.'*(N-i-1) for i in list(queens.values())]
solutions.append(sol.copy())
# 绘制当前解决方案
board = np.zeros((N,N))
for r,c in enumerate(list(queens.values())):
board[r][c]=1
draw_board(board)
plt.show(block=False)
plt.pause(delay)
plt.close()
else:
placequeen(row_num+1)
col_free[col_index] = True
up_free[row_num + col_index] = True
down_free[N - 1 + col_index - row_num] = True
placequeen(0)
return solutions
if __name__ == "__main__":
N = int(input("Enter number of Queens: "))
branch_and_bound_n_queens(N)
```
上述代码实现了基于分支限界的N皇后问题求解器,并利用`matplotlib`动态展示了每一步骤的结果。每次找到新的有效布局后都会暂停一段时间(`delay`)以便观察者能清楚看到变化[^1]。
阅读全文
相关推荐


















