在lar的环境下,初始状态,LED等全灭;按一下按键,LED灯全亮;再按一下,LED开始闪烁;再按一下,LED开始交替亮灭,0,2亮,然后1,3亮。若是再按按键则与第一次按键状态相同,如此循环。
时间: 2023-05-25 21:03:15 浏览: 95
以下是使用Arduino实现该功能的示例代码:
```
const int buttonPin = 2;
const int ledPin[] = { 3, 4, 5, 6 };
int ledState[] = { LOW, LOW, LOW, LOW };
int currentState = 0;
int lastState = 0;
unsigned long lastDebounceTime = 0;
unsigned long debounceDelay = 50;
bool ledOn = true;
bool blinkOn = false;
bool alternateOn = false;
void setup() {
pinMode(buttonPin, INPUT_PULLUP);
for (int i = 0; i < 4; i++) {
pinMode(ledPin[i], OUTPUT);
}
}
void loop() {
int currentState = digitalRead(buttonPin);
if (currentState != lastState) {
lastDebounceTime = millis();
}
if ((millis() - lastDebounceTime) > debounceDelay) {
if (currentState != currentState) {
currentState = currentState;
if (currentState == LOW) {
switchMode();
}
}
}
lastState = currentState;
if (ledOn) {
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], HIGH);
}
} else {
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], LOW);
}
}
if (blinkOn) {
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], !digitalRead(ledPin[i]));
}
}
if (alternateOn) {
digitalWrite(ledPin[0], HIGH);
digitalWrite(ledPin[2], HIGH);
digitalWrite(ledPin[1], LOW);
digitalWrite(ledPin[3], LOW);
delay(200);
digitalWrite(ledPin[0], LOW);
digitalWrite(ledPin[2], LOW);
digitalWrite(ledPin[1], HIGH);
digitalWrite(ledPin[3], HIGH);
delay(200);
}
}
void switchMode() {
ledOn = !ledOn;
blinkOn = false;
alternateOn = false;
if (ledOn) {
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], HIGH);
}
} else {
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], LOW);
}
}
delay(200);
blinkOn = true;
for (int i = 0; i < 4; i++) {
digitalWrite(ledPin[i], LOW);
}
alternateOn = true;
ledOn = false;
blinkOn = false;
}
```
这个代码使用了一个状态机来实现按下按键时的不同操作。在 `switchMode()` 函数中,LED 状态会在亮灭和交替之间循环,同时状态机会强制 LED 关闭,以便第二次按下按键时可以再次返回初始状态。注意,这个示例代码假设按键是连接到数字引脚 2,LED 则连接到数字引脚 3-6。如果接线有所不同,应相应地更改代码。
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