首页用java分别实现以下两个程序(1) 写两个线程，一个线程打印1——52，另一个线程打印A——Z，打印顺序为：12A34B...5152Z (2) 编程实现三线程程序，其中一个线程计算1-1000的累加和，另一个线程求100！，在主线程输出1-1000的累加和与100！。

用java分别实现以下两个程序(1) 写两个线程，一个线程打印1——52，另一个线程打印A——Z，打印顺序为：12A34B...5152Z (2) 编程实现三线程程序，其中一个线程计算1-1000的累加和，另一个线程求100！，在主线程输出1-1000的累加和与100！。

时间: 2024-05-13 17:16:33 浏览: 104

(1) ```java public class PrintThread implements Runnable { private int count = 1; private char ch = 'A'; @Override public void run() { synchronized (this) { while (count <= 52 && ch <= 'Z') { if (count % 2 == 1) { System.out.print(count++); System.out.print(count++); } else { System.out.print(ch++); } } } } } public class Main { public static void main(String[] args) { PrintThread printThread = new PrintThread(); new Thread(printThread).start(); } } ``` (2) ```java public class SumThread implements Runnable { private int sum = 0; @Override public void run() { for (int i = 1; i <= 1000; i++) { sum += i; } } public int getSum() { return sum; } } public class FactorialThread implements Runnable { private BigInteger factorial = BigInteger.ONE; @Override public void run() { for (int i = 2; i <= 100; i++) { factorial = factorial.multiply(BigInteger.valueOf(i)); } } public BigInteger getFactorial() { return factorial; } } public class Main { public static void main(String[] args) { SumThread sumThread = new SumThread(); FactorialThread factorialThread = new FactorialThread(); Thread thread1 = new Thread(sumThread); Thread thread2 = new Thread(factorialThread); thread1.start(); thread2.start(); try { thread1.join(); thread2.join(); } catch (InterruptedException e) { e.printStackTrace(); } System.out.println("1-1000的累加和为：" + sumThread.getSum()); System.out.println("100!的值为：" + factorialThread.getFactorial()); } } ```

阅读全文