yearData.stream().collect什么意思

要将原始数据转换为目标格式，需要执行以下步骤： 1. **解析输入数据**：提取年份（从`issueMonth`字段中获取），以及每个时间点的比率数据。 2. **按年份分组数据**：将每个月的比率数据归类到对应的年份中。 3. **按分数段组织数据**：将每个时间点的数据按照“分值”维度进行映射（如“1分”、“2分”等）。 4. **生成目标格式**：将上述整理后的数据按照目标结构输出。 下面是实现这一逻辑的 Java 代码示例： ```java import com.alibaba.fastjson.JSON; import java.util.*; public class DataTransformer { public static void main(String[] args) { String inputJson = "{\n" + " \"dimName\":\"模型分值\",\n" + " \"echatsName\":\"非私家车\",\n" + " \"map\":{\n" + " \"x\":[\"1\",\"2\",\"3\",\"4\",\"5\",\"6\",\"7\",\"8\",\"9\",\"10\",\"空\"],\n" + " \"y\":[\n" + " {\"name\":\"202401\",\"ratio\":[0.0534,0.0685,0.0639,0.0438,0.0517,0.0703,0.1261,0.147,0.2116,0.1004,0.0629]},\n" + " {\"name\":\"202402\",\"ratio\":[0.0632,0.0734,0.0698,0.0517,0.0579,0.0603,0.1577,0.1414,0.1645,0.0932,0.0662]},\n" + " {\"name\":\"202403\",\"ratio\":[0.0625,0.0749,0.0699,0.0537,0.0602,0.0601,0.147,0.1321,0.1919,0.0916,0.0556]},\n" + " {\"name\":\"202404\",\"ratio\":[0.0573,0.072,0.0676,0.047,0.0591,0.079,0.1259,0.1373,0.1881,0.1103,0.0557]},\n" + " {\"name\":\"202405\",\"ratio\":[0.0618,0.0617,0.068,0.0458,0.0554,0.0701,0.137,0.1422,0.1723,0.1352,0.05]},\n" + " {\"name\":\"202406\",\"ratio\":[0.0501,0.0599,0.0587,0.0479,0.0608,0.0688,0.1529,0.1267,0.1894,0.1307,0.0535]},\n" + " {\"name\":\"202407\",\"ratio\":[0.0488,0.0615,0.0637,0.0482,0.057,0.0727,0.1365,0.1305,0.1741,0.1359,0.0706]},\n" + " {\"name\":\"202408\",\"ratio\":[0.0502,0.1055,0.0605,0.0441,0.0545,0.061,0.1425,0.1281,0.1489,0.1105,0.0937]},\n" + " {\"name\":\"202409\",\"ratio\":[0.0571,0.072,0.0718,0.0496,0.0633,0.0722,0.1346,0.1284,0.1518,0.1038,0.095]},\n" + " {\"name\":\"202410\",\"ratio\":[0.0622,0.0739,0.0754,0.0514,0.0544,0.0854,0.1301,0.1341,0.153,0.0909,0.0887]},\n" + " {\"name\":\"202411\",\"ratio\":[0.0612,0.07,0.0666,0.0509,0.0583,0.0883,0.1213,0.1384,0.1495,0.1222,0.0727]},\n" + " {\"name\":\"202412\",\"ratio\":[0.0559,0.0753,0.0873,0.0426,0.0548,0.0741,0.13,0.1256,0.1416,0.1491,0.0628]},\n" + " {\"name\":\"202501\",\"ratio\":[0.0473,0.0631,0.0573,0.043,0.056,0.0824,0.1314,0.1562,0.1667,0.1215,0.0746]},\n" + " {\"name\":\"202502\",\"ratio\":[0.0554,0.0679,0.0696,0.0509,0.0609,0.0866,0.1546,0.1438,0.1402,0.1128,0.0568]},\n" + " {\"name\":\"202503\",\"ratio\":[0.0542,0.0763,0.0702,0.0508,0.0665,0.0831,0.1446,0.1402,0.1653,0.1137,0.0343]},\n" + " {\"name\":\"202504\",\"ratio\":[0.0514,0.0652,0.0603,0.0563,0.0714,0.0833,0.154,0.1298,0.1684,0.1226,0.0365]},\n" + " {\"name\":\"202505\",\"ratio\":[0.052,0.0583,0.0604,0.0474,0.0634,0.0764,0.1708,0.1344,0.1733,0.1215,0.0415]},\n" + " {\"name\":\"202506\",\"ratio\":[0.0511,0.0626,0.0681,0.0482,0.0587,0.0866,0.1492,0.1345,0.1805,0.1114,0.0484]}\n" + " ]\n" + " },\n" + " \"title\":\"签单月结构占比\",\n" + " \"type\":\"1\"\n" + "}"; InputData inputData = JSON.parseObject(inputJson, InputData.class); Map<String, Map<String, List<String>>> groupedByYearAndScore = new HashMap<>(); // Step 1: Transform data by year and score for (YItem item : inputData.map.y) { String year = item.name.substring(0, 4); int monthIndex = Integer.parseInt(item.name.substring(4)) - 1; groupedByYearAndScore.putIfAbsent(year, new HashMap<>()); Map<String, List<String>> scoreMap = groupedByYearAndScore.get(year); for (int i = 0; i < item.ratio.length; i++) { String scoreKey = (i + 1) + "分"; scoreMap.putIfAbsent(scoreKey, new ArrayList<>()); List<String> ratioList = scoreMap.get(scoreKey); if (ratioList.size() <= monthIndex) { for (int j = ratioList.size(); j <= monthIndex; j++) { ratioList.add(null); // Fill gaps with null } } ratioList.set(monthIndex, String.valueOf(item.ratio[i])); } } // Step 2: Build final structure OutputData output = new OutputData(); output.dimName = inputData.dimName; output.title = inputData.title; output.data = new HashMap<>(); for (Map.Entry<String, Map<String, List<String>>> entry : groupedByYearAndScore.entrySet()) { String year = entry.getKey(); Map<String, List<String>> scoreMap = entry.getValue(); List<Map<String, List<String>>> yearData = new ArrayList<>(); for (Map.Entry<String, List<String>> scoreEntry : scoreMap.entrySet()) { Map<String, List<String>> scoreItem = new HashMap<>(); scoreItem.put(scoreEntry.getKey(), scoreEntry.getValue()); yearData.add(scoreItem); } output.data.put(year, yearData); } // Step 3: Print result System.out.println(JSON.toJSONString(output, true)); } static class InputData { String dimName; String echatsName; MapData map; String title; String type; } static class MapData { List<String> x; List<YItem> y; } static class YItem { String name; double[] ratio; } static class OutputData { String dimName; Map<String, List<Map<String, List<String>>>> data; String title; } } ``` ### 解释： 1. **InputData 类**：用于反序列化原始 JSON 数据。 2. **groupedByYearAndScore 映射表**：将数据按年份和评分项分组。 3. **填充数据**：根据月份索引填充对应位置的数值。 4. **构造最终输出结构**：将处理好的数据组装成目标格式，并使用 FastJSON 输出结果。 --- ###

可以使用MATLAB的COM组件来实现将EXCEL中的一列数据每一天的数据累加成每一年的数据。具体步骤如下： 1.打开EXCEL文档并获取工作表对象。 ```matlab Excel = actxserver('Excel.Application'); Workbook = Excel.Workbooks.Open('文件路径'); Sheet = Workbook.Sheets.Item('工作表名'); ``` 2.获取要累加的列数据和日期数据，并将日期数据转换为年份。 ```matlab DataRange = Sheet.Range('A1:A100'); % 获取A1到A100列的数据 DateRange = Sheet.Range('B1:B100'); % 获取B1到B100列的日期数据 DateNum = datenum(DateRange.Value, 'mm/dd/yyyy'); % 将日期数据转换为Matlab序列号 YearNum = year(DateNum); % 获取每个日期的年份 ``` 3.使用MATLAB的unique函数获取所有年份，然后使用for循环遍历每个年份，对该年份的数据进行累加。 ```matlab Years = unique(YearNum); % 获取所有年份 for i = 1:length(Years) YearData = DataRange(YearNum == Years(i)); % 获取该年份的数据 TotalData = sum(YearData.Value); % 对该年份的数据进行累加 Sheet.Cells(i+1, 3).Value = Years(i); % 写入年份到第3列 Sheet.Cells(i+1, 4).Value = TotalData; % 写入累加结果到第4列 end ``` 4.关闭EXCEL文档和COM组件对象。 ```matlab Workbook.Save; Excel.Quit; delete(Excel); ``` 完整代码如下： ```matlab Excel = actxserver('Excel.Application'); Workbook = Excel.Workbooks.Open('文件路径'); Sheet = Workbook.Sheets.Item('工作表名'); DataRange = Sheet.Range('A1:A100'); DateRange = Sheet.Range('B1:B100'); DateNum = datenum(DateRange.Value, 'mm/dd/yyyy'); YearNum = year(DateNum); Years = unique(YearNum); for i = 1:length(Years) YearData = DataRange(YearNum == Years(i)); TotalData = sum(YearData.Value); Sheet.Cells(i+1, 3).Value = Years(i); Sheet.Cells(i+1, 4).Value = TotalData; end Workbook.Save; Excel.Quit; delete(Excel); ```