首页Python求1/1!+1/2!+1/3!+1/4!+.....+1/n!

Python求1/1!+1/2!+1/3!+1/4!+.....+1/n!

时间: 2023-12-07 18:40:08 浏览: 121

以下是Python求1/1!+1/2!+1/3!+1/4!+.....+1/n!的代码： ```python import math n = int(input("请输入n的值：")) sum = 0 for i in range(1, n+1): sum += 1 / math.factorial(i) print("1/1!+1/2!+1/3!+1/4!++1/n!的值为：", sum) ``` 输入n的值后，程序会计算出1/1!+1/2!+1/3!+1/4!+.....+1/n!的值并输出。

计算Sn-1+1/1!+1/2!+1/3!+1/4!+..+1/n!.并输出结果

以下是计算Sn-1+1/1!+1/2!+1/3!+1/4!+..+1/n!的Python代码，并输出结果： ```python import math n = int(input("请输入n的值：")) sum = 0 for i in range(n): sum += 1 / math.factorial(i) print("Sn-1+1/1!+1/2!+1/3!+1/4!+..+1/n!的值为：", sum) ```

编写一个函数,满足输入一个n,能够计算1+1/2!+1/3!+1/4!+......+1/n!

以下是Python代码实现： ```python import math def sum_factorial(n): if n == 1: return 1 else: return 1/math.factorial(n) + sum_factorial(n-1) n = int(input("请输入n的值：")) print("结果为：", sum_factorial(n)) ``` 输入n的值后，该函数将计算1+1/2!+1/3!+1/4!+......+1/n!的结果并输出。

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