Check whether two Strings are Anagram of each other using HashMap in Java Last Updated : 10 Jun, 2024 Summarize Comments Improve Suggest changes Share Like Article Like Report Write a function to check whether two given strings are an Anagram of each other or not. An anagram of a string is another string that contains the same characters, only the order of characters can be different. For example, "abcd" and "dabc" are an Anagram of each other. Approach: Hashmaps can be used to determine if two given strings are anagrams or not. The approach involves mapping the characters of each string to a hashmap, where the characters serve as keys and their frequencies as values. Then, the hashmaps for both strings are compared to check if they contain the same set of characters with the same frequencies. If the HashMaps are equal, the strings are considered anagrams; otherwise, they are not. Implementation: Java // Java code to check whether two strings // are Anagram or not using HashMap import java.util.HashMap; class GFG { // Function to check whether two strings // are an anagram of each other static boolean areAnagram(String str1, String str2) { if (str1.length() != str2.length()) { return false; } HashMap<Character, Integer> hmap1 = new HashMap<Character, Integer>(); char arr1[] = str1.toCharArray(); // Mapping first string for (char c : arr1) { hmap1.put(c, hmap1.getOrDefault(c, 0) + 1); } // Removing characters of second string from hashmap for (char c : str2.toCharArray()) { if (!hmap1.containsKey(c)) { return false; // If a character is not found in the hashmap, it's not an anagram } int count = hmap1.get(c); if (count == 1) { hmap1.remove(c); // Remove character if count is 1 } else { hmap1.put(c, count - 1); // Decrement count otherwise } } // If hashmap is empty, strings are anagrams return hmap1.isEmpty(); } // Test function public static void test(String str1, String str2) { System.out.println("Strings to be checked are:\n" + str1 + "\n" + str2 + "\n"); // Find the result if (areAnagram(str1, str2)) System.out.println("The two strings are " + "anagrams of each other\n"); else System.out.println("The two strings are not" + " anagrams of each other\n"); } // Driver program public static void main(String args[]) { // Get the Strings String str1 = "geeksforgeeks"; String str2 = "forgeeksgeeks"; // Test the Strings test(str1, str2); // Get the Strings str1 = "geeksforgeeks"; str2 = "geeks"; // Test the Strings test(str1, str2); } } OutputStrings to be checked are: geeksforgeeks forgeeksgeeks The two strings are anagrams of each other Strings to be checked are: geeksforgeeks geeks The two strings are not anagrams of each otherComplexity of the above Method:Time Complexity: O(l1 + l2) where l1 and l2 are lengths of strings.Auxiliary space: O(m1) where is the number of unique characters in str1. 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