C++ Program for Block swap algorithm for array rotation
Write a function rotate(ar[], d, n) that rotates arr[] of size n by d elements.
Rotation of the above array by 2 will make array
Algorithm :
Initialize A = arr[0..d-1] and B = arr[d..n-1]
1) Do following until size of A is equal to size of B
a) If A is shorter, divide B into Bl and Br such that Br is of same
length as A. Swap A and Br to change ABlBr into BrBlA. Now A
is at its final place, so recur on pieces of B.
b) If A is longer, divide A into Al and Ar such that Al is of same
length as B Swap Al and B to change AlArB into BArAl. Now B
is at its final place, so recur on pieces of A.
2) Finally when A and B are of equal size, block swap them.
Recursive Implementation:
- C++
C++
#include <bits/stdc++.h> using namespace std; /*Prototype for utility functions */void printArray(int arr[], int size); void swap(int arr[], int fi, int si, int d); void leftRotate(int arr[], int d, int n) { /* Return If number of elements to be rotated is zero or equal to array size */ if(d == 0 || d == n) return; /*If number of elements to be rotated is exactly half of array size */ if(n - d == d) { swap(arr, 0, n - d, d); return; } /* If A is shorter*/ if(d < n - d) { swap(arr, 0, n - d, d); leftRotate(arr, d, n - d); } else /* If B is shorter*/ { swap(arr, 0, d, n - d); leftRotate(arr + n - d, 2 * d - n, d); /*This is tricky*/ } } /*UTILITY FUNCTIONS*//* function to print an array */void printArray(int arr[], int size) { int i; for(i = 0; i < size; i++) cout << arr[i] << " "; cout << endl; } /*This function swaps d elements starting at index fi with d elements starting at index si */void swap(int arr[], int fi, int si, int d) { int i, temp; for(i = 0; i < d; i++) { temp = arr[fi + i]; arr[fi + i] = arr[si + i]; arr[si + i] = temp; } } // Driver Code int main() { int arr[] = {1, 2, 3, 4, 5, 6, 7}; leftRotate(arr, 2, 7); printArray(arr, 7); return 0; } // This code is contributed by rathbhupendra |
3 4 5 6 7 1 2
Time Complexity: O(N), where N represents the size of the given array.
Auxiliary Space: O(N), due to recursive stack space .
Iterative Implementation:
Here is iterative implementation of the same algorithm. Same utility function swap() is used here.
- C++
C++
// C++ code for above implementation void leftRotate(int arr[], int d, int n) { int i, j; if (d == 0 || d == n) return; i = d; j = n - d; while (i != j) { if (i < j) /*A is shorter*/ { swap(arr, d - i, d + j - i, i); j -= i; } else /*B is shorter*/ { swap(arr, d - i, d, j); i -= j; } // printArray(arr, 7); } /*Finally, block swap A and B*/ swap(arr, d - i, d, i); } // This code is contributed by Shivani |
Time Complexity: O(N), where N represents the size of the given array.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please see following posts for other methods of array rotation:
https://www.geeksforgeeks.org/array-rotation/
https://www.geeksforgeeks.org/program-for-array-rotation-continued-reversal-algorithm/
Please write comments if you find any bug in the above programs/algorithms or want to share any additional information about the block swap algorithm.
Please refer complete article on Block swap algorithm for array rotation for more details!
