Find the Nth term of the series 14, 28, 20, 40,..... Last Updated : 08 Jul, 2022 Comments Improve Suggest changes Like Article Like Report Given a number N . The task is to find the N-th term in the following series: 14, 28, 20, 40, 32, 64..... Examples: Input : N = 5 Output : 32 Input : N = 6 Output : 64 Approach: Initialize first number with 14.Run a loop from i = 2 to N and do following steps: For Even i, double the previous term. For example if i = 2, current term will be 2*(term when i = 1), that is 2*14 = 28.For Odd i, subtract 8 from the previous term.Exit the loop and print the final number. Below is the implementation of the above approach: C++ // CPP program to find the Nth term of // the series 14, 28, 20, 40, ….. #include <iostream> using namespace std; // Function to find the N-th term int findNth(int N) { // initializing the 1st number int b = 14; int i; // loop from 2nd term to nth term for (i = 2; i <= N; i++) { // if i is even, double the // previous number if (i % 2 == 0) b = b * 2; // if i is odd, subtract 8 from // previous number else b = b - 8; } return b; } // Driver Code int main() { int N = 6; cout << findNth(N); return 0; } Java // Java program to find the Nth term of // the series 14, 28, 20, 40, import java.io.*; class GFG { // Function to find the N-th term static int findNth(int N) { // initializing the 1st number int b = 14; int i; // loop from 2nd term to nth term for (i = 2; i <= N; i++) { // if i is even, double the // previous number if (i % 2 == 0) b = b * 2; // if i is odd, subtract 8 from // previous number else b = b - 8; } return b; } // Driver Code public static void main (String[] args) { int N = 6; System.out.print(findNth(N)); } } // This code is contributed by shs Python 3 # Python 3 program to find the Nth term # of the series 14, 28, 20, 40, ….. # Function to find the N-th term def findNth(N): # initializing the 1st number b = 14 # loop from 2nd term to nth term for i in range (2, N + 1): # if i is even, double the # previous number if (i % 2 == 0): b = b * 2 # if i is odd, subtract 8 from # previous number else: b = b - 8 return b # Driver Code N = 6 print(findNth(N)) # This code is contributed # by Akanksha Rai C# // C# program to find the Nth term of // the series 14, 28, 20, 40, using System; public class GFG{ // Function to find the N-th term static int findNth(int N) { // initializing the 1st number int b = 14; int i; // loop from 2nd term to nth term for (i = 2; i <= N; i++) { // if i is even, double the // previous number if (i % 2 == 0) b = b * 2; // if i is odd, subtract 8 from // previous number else b = b - 8; } return b; } // Driver Code static public void Main (){ int N = 6; Console.WriteLine(findNth(N)); } } // This code is contributed by ajit PHP <?php // PHP program to find the Nth term of // the series 14, 28, 20, 40, ….. // Function to find the N-th term function findNth($N) { // initializing the 1st number $b = 14; // loop from 2nd term to nth term for ($i = 2; $i <= $N; $i++) { // if i is even, double the // previous number if ($i % 2 == 0) $b = $b * 2; // if i is odd, subtract 8 from // previous number else $b = $b - 8; } return $b; } // Driver Code $N = 6; echo findNth($N); // This code is contributed by akt_mit ?> JavaScript <script> // java script program to find the Nth term of // the series 14, 28, 20, 40, ….. // Function to find the N-th term function findNth(N) { // initializing the 1st number let b = 14; // loop from 2nd term to nth term for (let i = 2; i <= N; i++) { // if i is even, double the // previous number if (i % 2 == 0) b = b * 2; // if i is odd, subtract 8 from // previous number else b = b - 8; } return b; } // Driver Code N = 6; document.write(findNth(N)); // This code is contributed // by pulamolu mohan pavan cse </script> Output: 64 Time Complexity: O(N) Auxiliary Space: O(1) Comment More infoAdvertise with us Next Article Analysis of Algorithms R Rohit_ranjan Follow Improve Article Tags : DSA Technical Scripter 2018 series school-programming Practice Tags : series Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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