How to delete last N rows from Numpy array?

Last Updated : 28 Apr, 2021

In this article, we will discuss how to delete the last N rows from the NumPy array.

Method 1: Using Slice Operator

Slicing is an indexing operation that is used to iterate over an array.

Syntax: array_name[start:stop]

where start is the start is the index and stop is the last index.

We can also do negative slicing in Python. It is denoted by the below syntax.

Syntax: array_name[: -n]

where, n is the number of rows from last to be deleted.

Example1:

We are going to create an array with 6 rows and 3 columns and delete last N rows using slicing.

Python3

# importing numpy module 
import numpy as np 
  
# create an array with 6 rows and 3 columns 
a = np.array([[1, 2, 3], [4, 5, 6], [7, 8, 9],  
              [10, 11, 12], [13, 14, 15], [16, 17, 18]]) 
  
print(a) 
  
# delete last 1 st row 
print("data after deleting last one row ", a[:-1]) 
  
# delete last 2 nd  row 
print("data after deleting last two  rows ", a[:-2]) 
  
# delete last 3 rd  row 
print("data after deleting last theww  rows ", a[:-3]) 
  
# delete last 4 th  row 
print("data after deleting last four  rows ", a[:-4]) 
  
# delete last 5 th  row 
print("data after deleting last five  rows ", a[:-5]) 
  
# delete last 6 th  row 
print("data after deleting last six  rows ", a[:-6]) 

Output:

Example 2:

We use for loop to iterate over the elements and use the slice operator, we are going to delete the data and then print the data.

Python3

# importing numpy module 
import numpy as np 
  
# create an array with 5 rows and  
# 4 columns 
a = np.array([[21, 7, 8, 9], [34, 10, 11, 12],  
              [1, 3, 14, 15], [1, 6, 17, 18],  
              [4, 5, 6, 7]]) 
  
# use for loop to iterate over the 
# elements 
for i in range(1, len(a)+1): 
    print("Iteration No", i, "deleted", i, "Rows") 
    print("Remaining data present in the array is\n ", a[:-i])

Output:

Example 3:

We can also specify the elements that we need and store them into another array variable using the slice operator. In this way, we will not get the last N rows (delete those).

Python3

# importing numpy module 
import numpy as np 
  
# create an array with 5 rows and  
# 4 columns 
a = np.array([[21, 7, 8, 9], [34, 10, 11, 12],  
              [1, 3, 14, 15], [1, 6, 17, 18], 
              [4, 5, 6, 7]]) 
  
# place first 2 rows in b variable  
# using slice operator 
b = a[:2] 
  
print(b) 

Output:

[[21  7  8  9]
 [34 10 11 12]]

Method 2: Using numpy.delete() method

It is used to delete the elements in a NumPy array based on the row number.

Syntax: numpy.delete(array_name,[rownumber1,rownumber2,.,rownumber n],axis)

Parameters:

array_name is the name of the array.

row numbers is the row values

axis specifies row or column

axis=0 specifies row

axis=1 specifies column

Here we are going to delete the last rows so specify the rows numbers in the list.

Example 1: Delete last three rows

Python3

# importing numpy module 
import numpy as np 
  
# create an array with 5 rows and  
# 4 columns 
a = np.array([[21, 7, 8, 9], [34, 10, 11, 12],  
              [1, 3, 14, 15], [1, 6, 17, 18],  
              [4, 5, 6, 7]]) 
  
# delete last three rows 
# using numpy.delete 
a = np.delete(a, [2, 3, 4], 0) 
print(a) 

Output:

[[21  7  8  9]
 [34 10 11 12]]

Example 2: Delete all rows

Python3

# importing numpy module 
import numpy as np 
  
# create an array with 5 rows and 4 columns 
a = np.array([[21, 7, 8, 9], [34, 10, 11, 12],  
              [1, 3, 14, 15], [1, 6, 17, 18],  
              [4, 5, 6, 7]]) 
  
# delete last three rows 
# using numpy.delete 
a = np.delete(a, [0, 1, 2, 3, 4], 0) 
print(a) 

Output:

[ ]

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How to delete last N rows from Numpy array?

Method 1: Using Slice Operator

Python3

Python3

Python3

Method 2: Using numpy.delete() method

Python3

Python3

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