How to Get the String in Specified Base in Golang?

Go language provides inbuilt support to implement conversions to and from string representations of basic data types by strconv Package. This package provides a FormatInt() function which is used to return the string representation of x in the given base, i.e., 2 <= base <= 36. Here, the result uses the lower-case letters 'a' to 'z' for digit values which is greater than equals to 10. To access FormatInt() function you need to import strconv Package in your program with the help of import keyword. Syntax:

func FormatInt(x int64, base int) string

Parameter: This function takes two parameters, i.e., x and base. Return value: This function returns the string representation of x in the given base, i.e., 2 <= base <= 36. Let us discuss this concept with the help of the given examples: Example 1: C

// Golang program to illustrate
// strconv.FormatInt() Function
package main

import (
    "fmt"
    "strconv"
)

func main() {
    // Finding the string representation
    // of given value in the given base
    // Using FormatInt() function
    fmt.Println(strconv.FormatInt(23, 2))
    fmt.Println(strconv.FormatInt(-24, 10))

}

Output:

10111
-24

Example 2: C

// Golang program to illustrate
// strconv.FormatInt() Function
package main

import (
    "fmt"
    "strconv"
)

func main() {

    // Finding the string representation
    // of given value in the given base
    // Using FormatInt() function
    val1 := int64(25)
    res1 := strconv.FormatInt(val1, 2)
    fmt.Printf("Result 1: %v", res1)
    fmt.Printf("\nType 1: %T", res1)

    val2 := int64(-50)
    res2 := strconv.FormatInt(val2, 16)
    fmt.Printf("\nResult 2: %v", res2)
    fmt.Printf("\nType 2: %T", res2)

}

Output:

Result 1: 11001
Type 1: string
Result 2: -32
Type 2: string