How to select all elements that contains some specific CSS property using jQuery ?

Last Updated : 29 Jan, 2020

Given a HTML document containing elements and some elements have specific CSS properties. The task is to select all elements having the same property value pair in them. There are two approaches that are discussed below:

Approach 1: First select the elements in which we want to check for the same properties using jQuery Selector. Use filter() method on every element and return the value true if the particular CSS property matches with it’s CSS. Now, we have all elements with same CSS property value pair. Get the ID of them to identify which elements are selected.

Example: This example implements the above approach.

<!DOCTYPE HTML> 
<html> 
  
<head> 
    <title> 
        How to select all elements that contains 
        some specific CSS property using jQuery ? 
    </title> 
      
    <script src= 
"https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"> 
    </script> 
</head> 
  
<body style="text-align:center;"> 
      
    <h1 style="color:green;">  
        GeeksforGeeks  
    </h1> 
      
    <p id="gfg" style= 
            "font-size: 20px;font-weight: bold;"> 
        Click on the button to get the ID's 
        of selected elements having same 
        property value pair.<br>CSS-  
        'font-weight: bold' 
    </p> 
      
    <button onclick="GFG_Fun();"> 
        Click Here 
    </button> 
      
    <p id="geeks" style= 
        "font-size: 24px; font-weight: bold; 
        color: green;"> 
    </p> 
      
    <script> 
        var down = document.getElementById('geeks'); 
  
        function GFG_Fun() { 
            var x = $('p').filter(function() { 
                return this.style.fontWeight == 'bold' 
            }); 
              
            down.innerHTML = "ID's of selected " 
                + "elements are - <br>" + x[0].id 
                + "<br>" + x[1].id; 
        } 
    </script> 
</body> 
  
</html> 

Output:

Approach 2: First select the elements in which we want to check for the same properties using jQuery Selector. Use not() method on every element and return the value true if the particular CSS property does not match with its CSS. Now, We have all elements with some CSS property the same, Get the ID of them to identify which elements are selected.

Example: This example implements the above approach.

<!DOCTYPE HTML> 
<html> 
  
<head> 
    <title> 
        How to select all elements that contains 
        some specific CSS property using jQuery ? 
    </title> 
      
    <script src= 
"https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"> 
    </script> 
</head> 
  
<body style="text-align:center;"> 
      
    <h1 style="color:green;">  
        GeeksforGeeks  
    </h1> 
      
    <p id="gfg" style="font-size: 20px; 
                    font-weight: bold;"> 
        Click on the button to get the 
        ID's of selected elements having 
        same property value pair.<br>CSS- 
        'font-size: 20px' 
    </p> 
      
    <button onclick="GFG_Fun();"> 
        Click Here 
    </button> 
      
    <p id="geeks" style= 
            "font-size: 20px; font-weight: bold;  
            color: green;"> 
    </p> 
      
    <script> 
        var down = document.getElementById('geeks'); 
  
        function GFG_Fun() { 
              
            /* Using not method, which removes 
                the elements which don't matches 
                the property. */ 
            var x = $('p').not(function() { 
                return $(this).css('font-size') != '20px'; 
            }); 
              
            down.innerHTML = "ID's of selected " 
                    + "elements are - <br>" + x[0].id 
                    + "<br>" + x[1].id; 
        } 
    </script> 
</body> 
  
</html>              

Output:

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PranchalKatiyar

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How to select all elements that contains some specific CSS property using jQuery ?

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