Angle Sum Property of a Triangle is the special property of a triangle that is used to find the value of an unknown angle in the triangle. It is applicable to any of the triangles whether it is a right, acute, obtuse angle triangle or any other type of triangle. For a closed polygon, the sum of all the interior angles is dependent on the sides of the polygon.
In a triangle sum of all the interior angles is equal to 180 degrees.
Formula
The angle sum property formula used for any polygon is given by the expression,
Sum of Interior Angle = (n − 2) × 180°
where 'n' is the number of sides of the polygon.
According to this property, the sum of the interior angles of the polygon depends on how many triangles are formed inside the polygon, i.e. for 1 triangle the sum of interior angles is 1×180° for two triangles inside the polygon the sum of interior angles is 2×180° similarly for a polygon of 'n' sides, (n - 2) triangles are formed inside it.
Example:Find the sum of the interior angles for the pentagon.
Theorem 1: The angle sum property of a triangle states that the sum of interior angles of a triangle is 180°.
Proof: The sum of all the angles of a triangle is equal to 180°. This theorem can be proved by the below-shown figure.
Follow the steps given below to prove the angle sum property in the triangle.
Step 1: Draw a line parallel to any given side of a triangle let's make a line AB parallel to side RQ of the triangle.
Step 2: We know that sum of all the angles in a straight line is 180°. So, ∠APR + ∠RPQ + ∠BPQ = 180°
Step 3: In the given figure as we can see that side AB is parallel to RQ and RP, and QP act as a transversal. So we can see that angle ∠APR = ∠PRQ and ∠BPQ = ∠PQR by the property of alternate interior angles .
From step 2 and step 3,
∠PRQ + ∠RPQ + ∠PQR = 180° [Hence Proved]
Example: In the given triangle PQR if the given is ∠PQR = 30°, ∠QRP = 70°then find the unknown ∠RPQ
As we know that, sum of all the angle of triangle is 180°
∠PQR + ∠QRP + ∠RPQ = 180°
⇒ 30° + 70° + ∠RPQ = 180°
⇒ 100° + ∠RPQ = 180°
⇒ ∠RPQ = 180° - 100°
⇒ ∠RPQ = 80°
Exterior Angle Property of a Triangle Theorem
Theorem 2: If any side of a triangle is extended, then the exterior angle so formed is the sum of the two opposite interior angles of the triangle.
Proof:
As we have proved the sum of all the interior angles of a triangle is 180° (∠ACB + ∠ABC + ∠BAC = 180°) and we can also see in figure, that ∠ACB + ∠ACD = 180° due to the straight line. By the above two equations, we can conclude that
∠ACD = 180° - ∠ACB
⇒ ∠ACD = 180° - (180° - ∠ABC - ∠CAB)
⇒ ∠ACD = ∠ABC + ∠CAB
Hence proved that If any side of a triangle is extended, then the exterior angle so formed is the sum of the two opposite interior angles of the triangle.
Solved Example on Angle Sum Property of a Triangle
Example 1: It is given that a transversal line cuts a pair of parallel lines and the ∠1: ∠2 = 4: 5 as shown in figure 9. Find the measure of the ∠3?
As we are given that the given pair of a line are parallel so we can see that ∠1 and ∠2 are consecutive interior angles and we have already studied that consecutive interior angles are supplementary.
Therefore let us assume the measure of ∠1 as '4x' therefore ∠2 would be '5x'
As we can clearly see in the figure that ∠3 and ∠2 are alternate interior angles so ∠3 = ∠2
∠3 = 100°.
Example 2: As shown in Figure below angle APQ = 120° and angle QRB = 110°. Find the measure of the angle PQR given that the line AP is parallel to line RB.
As we are given that line AP is parallel to line RB
We know that the line perpendicular to one would surely be perpendicular to the other. So let us make a line perpendicular to both the parallel line as shown in the picture.
Now as we can clearly see that
∠APM + ∠MPQ = 120° and as PM is perpendicular to line AP so ∠APM = 90° therefore,
⇒ ∠MPQ = 120° - 90° = 30°.
Similarly, we can see that ∠ORB = 90° as OR is perpendicular to line RB therefore,
∠QRO = 110° - 90° = 20°.
Line OR is parallel to line QN and MP therefore,
∠PQN = ∠MPQ as they both are alternate interior angles. Similarly,
