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Postorder Traversal of Binary Tree in Python

Last Updated : 22 Feb, 2025
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Postorder traversal is defined as a type of tree traversal which follows the Left-Right-Root policy such that for each node:

  • The left subtree is traversed first
  • Then the right subtree is traversed
  • Finally, the root node of the subtree is traversed

Consider the following tree:

post1

If we perform a postorder traversal in this binary tree, then the traversal will be as follows:

Step-by-step approach:

  • Step 1: The traversal will go from 1 to its left subtree i.e., 2, then from 2 to its left subtree root, i.e., 4. Now 4 has no subtree, so it will be visited.
  • Step 2: As the left subtree of 2 is visited completely, now it will traverse the right subtree of 2 i.e., it will move to 5. As there is no subtree of 5, it will be visited.
  • Step 3: Now both the left and right subtrees of node 2 are visited. So now visit node 2 itself.
  • Step 4: As the left subtree of node 1 is traversed, it will now move to the right subtree root, i.e., 3. Node 3 does not have any left subtree, so it will traverse the right subtree i.e., 6. Node 6 has no subtree and so it is visited.
  • Step 5: All the subtrees of node 3 are traversed. So now node 3 is visited.
  • Step 6: As all the subtrees of node 1 are traversed, now it is time for node 1 to be visited and the traversal ends after that as the whole tree is traversed.

So the order of traversal of nodes is 4 -> 5 -> 2 -> 6 -> 3 -> 1.

Examples of Postorder Traversal

Input:

postorder_traversal_of_binary_tree

Output: BCA
Explanation: The Post Order Traversal visits the nodes in the following order: Left, Right, Root. Therefore, we visit the left node B, then the right node C and lastly the root node A.

Input:

postorder_traversal_of_binary_tree_1

Output: DEBCA

Input: NULL
Output:
Explanation: Since the tree has no nodes, output is empty in this case.

Algorithm for Postorder Traversal of Binary Tree

The algorithm for postorder traversal is shown as follows:

Postorder(root):

  1. If root is NULL then return
  2. Postorder (root -> left)
  3. Postorder (root -> right)
  4. Process root (For example, print(root->data))

Python Program to implement Postorder Traversal of Binary Tree

Below is the code implementation of the postorder traversal:

Python
# Python program for postorder traversals

# Structure of a Binary Tree Node
class Node:
    def __init__(self, v):
        self.data = v
        self.left = None
        self.right = None

# Function to print postorder traversal
def printPostorder(node):
    if node == None:
        return

    # First recur on left subtree
    printPostorder(node.left)

    # Then recur on right subtree
    printPostorder(node.right)

    # Now deal with the node
    print(node.data, end=' ')


# Driver code
if __name__ == '__main__':
    root = Node(1)
    root.left = Node(2)
    root.right = Node(3)
    root.left.left = Node(4)
    root.left.right = Node(5)
    root.right.right = Node(6)

    # Function call
    print("Postorder traversal of binary tree is:")
    printPostorder(root)

Output
Postorder traversal of binary tree is:
4 5 2 6 3 1 

Complexity Analysis:

Time Complexity: O(n) where n is the total number of nodes. Because it traverses all the nodes at least once.
Auxiliary Space: O(1) if no recursion stack space is considered. Otherwise, O(h) where h is the height of the tree

  • In the worst case, h can be the same as n (when the tree is a skewed tree)
  • In the best case, h can be the same as log n (when the tree is a complete tree)

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