Print the given 3 string after modifying and concatenating

Last Updated : 13 Mar, 2023

Given three strings(without spaces). The task is to print the new string after modifying the three given string as follows:

Replace all the vowels present in the first string with “*”.
Don’t change anything in the second string.
Replace all the consonants in the third string with “$”.
Concatenate all of the three string to obtain the new string.

Examples:

Input: how are you
Output\: h*ware$ou

Input: geeks for geeks
Output: g**ksfor$ee$$

Approach:
The idea is to traverse the first string and keep checking if any character is a vowel or not. Replace the character in the first string which is vowel with “*”. Similarly, traverse the third string and keep checking if any character is not a vowel. If a character in the third string is not a vowel(then it is a consonant), replace it with ‘$’.
Finally, concatenate the three strings and print the newly concatenated string.

Below is the implementation of the above approach:

C++

// CPP program to modify the given strings 
#include <iostream> 
#include <string.h> 
using namespace std; 
  
// Function to modify the given three strings 
string modifyStr(string str1, string str2, string str3) 
{ 
    // Modifying first string 
    for (int i = 0; i < str1.length(); i++) { 
        if (str1[i] == 'a' || str1[i] == 'e' ||  
            str1[i] == 'i' || str1[i] == 'o' ||  
            str1[i] == 'u') 
            str1[i] = '*'; 
    } 
  
    // Modifying third string 
    for (int i = 0; i < str3.length(); i++) { 
        if (str3[i] != 'a' && str3[i] != 'e' &&  
            str3[i] != 'i' && str3[i] != 'o' &&  
            str3[i] != 'u') 
            str3[i] = '$'; 
    } 
  
    // Concatenating the three strings 
    return (str1 + str2 + str3); 
} 
  
// Driver code 
int main() 
{ 
    string str1 = "how"; 
    string str2 = "are"; 
    string str3 = "you"; 
  
    cout << modifyStr(str1, str2, str3); 
  
    return 0; 
} 

Java

// JAVA program to modify the given Strings 
class GFG 
{ 
  
// Function to modify the given three Strings 
static String modifyStr(String str1, String str2, String str3) 
{ 
    // Modifying first String 
    for (int i = 0; i < str1.length(); i++) { 
        if (str1.charAt(i) == 'a' || str1.charAt(i) == 'e' ||  
            str1.charAt(i) == 'i' || str1.charAt(i) == 'o' ||  
            str1.charAt(i) == 'u') 
            str1 = str1.substring(0, i)+ '*' +  
                   str1.substring(i + 1); 
    } 
  
    // Modifying third String 
    for (int i = 0; i < str3.length(); i++) { 
        if (str3.charAt(i) != 'a' && str3.charAt(i) != 'e' &&  
            str3.charAt(i) != 'i' && str3.charAt(i) != 'o' &&  
            str3.charAt(i) != 'u') 
            str3 = str3.substring(0, i)+ '$' +  
                   str3.substring(i + 1); 
    } 
  
    // Concatenating the three Strings 
    return (str1 + str2 + str3); 
} 
  
// Driver code 
public static void main(String[] args) 
{ 
    String str1 = "how"; 
    String str2 = "are"; 
    String str3 = "you"; 
  
    System.out.print(modifyStr(str1, str2, str3)); 
} 
} 
  
// This code is contributed by 29AjayKumar 

Python3

# Python3 program to modify the given Strings 
  
# Function to modify the given three Strings 
def modifyStr(str1, str2, str3): 
      
    # Modifying first String 
    for i in range(len(str1)): 
        if (str1[i] == 'a' or str1[i] == 'e' or
            str1[i] == 'i' or str1[i] == 'o'
            or str1[i] == 'u'): 
            str1 = str1[0:i] + '*' + str1[i + 1:]; 
      
  
    # Modifying third String 
    for i in range(len(str3)): 
        if (str3[i] != 'a' and str3[i] != 'e' and 
            str3[i] != 'i' and str3[i] != 'o'
            and str3[i] != 'u'): 
            str3 = str3[0: i] + '$' + str3[i + 1:]; 
      
    # Concatenating the three Strings 
    return (str1 + str2 + str3); 
  
# Driver code 
if __name__ == '__main__': 
    str1 = "how"; 
    str2 = "are"; 
    str3 = "you"; 
  
    print(modifyStr(str1, str2, str3)); 
      
# This code is contributed by 29AjayKumar 

C#

// C# program to modify the given Strings 
using System; 
  
class GFG 
{ 
  
// Function to modify the given three Strings 
static String modifyStr(String str1, String str2, String str3) 
{ 
    // Modifying first String 
    for (int i = 0; i < str1.Length; i++)  
    { 
        if (str1[i] == 'a' || str1[i] == 'e' ||  
            str1[i] == 'i' || str1[i] == 'o' ||  
            str1[i] == 'u') 
            str1 = str1.Substring(0, i)+ '*' +  
                str1.Substring(i + 1); 
    } 
  
    // Modifying third String 
    for (int i = 0; i < str3.Length; i++) 
    { 
        if (str3[i] != 'a' && str3[i] != 'e' &&  
            str3[i] != 'i' && str3[i] != 'o' &&  
            str3[i] != 'u') 
            str3 = str3.Substring(0, i)+ '$' +  
                str3.Substring(i + 1); 
    } 
  
    // Concatenating the three Strings 
    return (str1 + str2 + str3); 
} 
  
// Driver code 
public static void Main(String[] args) 
{ 
    String str1 = "how"; 
    String str2 = "are"; 
    String str3 = "you"; 
  
    Console.Write(modifyStr(str1, str2, str3)); 
} 
} 
  
// This code is contributed by PrinciRaj1992 

Javascript

<script> 
  
// Javascript program to modify the given Strings 
  
// Function to modify the given three Strings 
function modifyStr(str1, str2, str3) 
{ 
    // Modifying first String 
    for(var i = 0; i < str1.length; i++) 
    { 
        if (str1.charAt(i) == 'a' ||  
            str1.charAt(i) == 'e' ||  
            str1.charAt(i) == 'i' ||  
            str1.charAt(i) == 'o' ||  
            str1.charAt(i) == 'u') 
            str1 = str1.substring(0, i) + '*' +  
                   str1.substring(i + 1); 
    } 
  
    // Modifying third String 
    for(var i = 0; i < str3.length; i++)  
    { 
        if (str3.charAt(i) != 'a' &&  
            str3.charAt(i) != 'e' &&  
            str3.charAt(i) != 'i' &&  
            str3.charAt(i) != 'o' &&  
            str3.charAt(i) != 'u') 
            str3 = str3.substring(0, i) + '$' +  
                   str3.substring(i + 1); 
    } 
  
    // Concatenating the three Strings 
    return (str1 + str2 + str3); 
} 
  
// Driver code 
var str1 = "how"; 
var str2 = "are"; 
var str3 = "you"; 
  
document.write(modifyStr(str1, str2, str3)); 
  
// This code is contributed by Ankita saini 
  
</script>

Output:

h*ware$ou

Time Complexity: O(m+n), where m is the length of the first string and n is the length of the third string.

Auxiliary Space: O(1), as constant extra space is required.

Concatenate suffixes of a String

Smitha Dinesh Semwal

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Article Tags :

Print the given 3 string after modifying and concatenating

C++

Java

Python3

C#

Javascript

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