In discrete mathematics, a tautology is a compound statement that is always true, regardless of the truth values of its individual components. It is a fundamental concept in propositional logic, used to verify logical expressions and implications. Tautologies play a crucial role in constructing proofs and understanding logical consistency.
What is Proposition?
The meaning of proposition in literature is an idea, a plan an offer, or a suggestion that can be proved True or False. The same goes for mathematical propositions. They are declarative sentences that can be True or False. Propositions are the fundamental building blocks of logic.
Examples:
1. The magnetic lines emerge from the North and merge into South pole.
2. 2 + 1 = 3
3. 'p' is a vowel.
All of the above three sentences are proper propositions, where the first two are True and the third one is False.
Tautology
Propositional logic is said to be a tautology if it is always true regardless of the true/false of the atomic formulas. A tautology is always “True". To check whether a given logic is a tautology or not, we often use the truth table method. However, the truth table method is not effective when the logic contains several atomic formulas.
Example:
Odd number = A
Even number = B
1. If we add one odd number and one even number then we get odd number.
Converting statement-1 into mathematical logic:
A ∧ B ⇒ A
Let's prove that the above logic is a tautology. In order to build the truth table, we need to convert the logic statements into a clausal form.
The truth table of A ∧ B ⇒ A, clausal form is: ¬(A ∧ B)∨A
A | B | (A ∧ B) | ¬(A ∧ B) | ¬(A ∧ B)∨A |
---|
T | T | T | F | T |
T | F | F | F | T |
F | T | F | T | T |
F | F | F | T | T |
All entries are True, irrespective of the True/False values of atomic literals. So, this is a tautology.
Examples of Tautology with logic symbols:
- ¬A∨A
- (P∨Q)⇒(P∨Q)
A mathematical sentence consisted of logic. A proposition is either True or False. The proposition is made up of mathematical logic. Various propositional logics are given below in their priority order:
- Negation (No)
- Conjunction (and)
- Disjunction (or)
- Implication (⇒)
- Equivalence (⇔)
Tautology- A proposition that is always true. The truth table is evaluated for the given proposition and if in every case the result is True, then that proposition is called Tautology.
Truth Table
It is a table that gives the output of the propositional logic against each input component. The result is binary, either True or False for each row of inputs.
Problems on Tautology
Find if the given propositional logic is a tautology or not.
1) P
Truth table:
The truth table of P contains a False value. Thus, it can not be a tautology.
2) P⇒P
We shall draw the truth table for this proposition.
Implication:
P⇒Q =¬P∨Q
The simplified expression of the given proposition is: ¬P∨P
Truth Table:
The truth table of ¬P∨P consists only of True values. Therefore, P⇒P is a tautology.
3) (P ⇒ P) ⇒ P
We shall draw the truth table for this proposition.
Implication:
P⇒Q=¬P∨Q
The simplified expression of the given proposition is:
(¬P∨P) ⇒ P
¬(¬P∨P)∨P
(¬(¬P) ∧ ¬P)∨P {By Demorgan's Law}
(P ∧ ¬P) ∨P
(P ∧ ¬P)= False {Complement laws: – P∧¬P=F }
False ∨ P = P {Absorption law}
Thus, (P ⇒ P) ⇒ P is equivalent to P. We have already solved this in problem-1.
Therefore, this is not a Tautology.
4) (p → q) → [(p → q) → q]
Solving: (p → q) = ¬p∨q {Implication}
Solving: [(p → q) → q]
= [(¬p∨q) → q]
= [¬(¬p∨q)∨q]
= [(¬(¬p)∧¬q)∨q] {Demorgan's Law}
= [(p∧¬q)∨q] {Involution law}
= [(p∨q)∧(¬q∨q)] {Distributive law}
= [(p∨q)∧T] {Complement law}
= (p∨q) {Absorption law}
Solving (p → q) → [(p → q) → q]
¬(¬p∨q)∨(p∨q)
[¬(¬p)∧(¬q)]∨(p∨q){Demorgan's Law}
(p∧¬q)∨(p∨q) {Involution law}
Thus, final expression is: (p∧¬q)∨(p∨q)
Truth Table:
p | q | ¬q | (p∧¬q) | (p∨q) | (p∧¬q)∨(p∨q) |
---|
T | T | F | F | T | T |
T | F | T | T | T | T |
F | T | F | F | T | T |
F | F | T | F | F | F |
Since there is a False entry in the truth table, it implies it is not a Tautology.
5) ((P⇒Q)∧P)⇒Q
Solving (P⇒Q): ¬P∨Q
Solving ((P⇒Q)∧P): ((¬P∨Q)∧P)
= (¬P∧P)∨(Q∧P) {Distributive Law}
= (F)∨(Q∧P) {Complement Law}
= (Q∧P) {Absorption Law}
Solving ((P⇒Q)∧P)⇒Q: (Q∧P)⇒Q
= ¬(Q∧P)∨Q
= (¬Q∨¬P)∨Q {Demorgan Law}
= (¬Q∨Q)∨¬P) {Associative Law}
= T∨(¬P) {Complement Law}
= T {Absorption Law}
Final CNF is: True
Here, no need of finding the Truth Table. Given logic is a tautology.
Related Articles:
Conclusion
Understanding and identifying tautologies are essential skills in discrete mathematics and logic. They help ensure the correctness and consistency of logical statements and are widely used in mathematical proofs and algorithm design. By practicing problems related to tautologies, students can enhance their logical reasoning and problem-solving abilities.
Practice Problems on Tautology
1. Verify if p ∨ ¬p is a tautology.
2. Check if p ∧ ¬p is a tautology.
3. Determine if q → (p ∨ q) is a tautology.
4. Test if (p ∨ q) ∧ ¬p ∧ ¬q is a tautology.
5. Validate if (p ∧ q) → p is a tautology.
6. Determine if (p → q) ∨ (q → p) is a tautology.
7. Check if [(p → q) ∧ (q → r)] → (p → r) is a tautology.
8. Verify if p → (q → p) is a tautology.
9. Test if (p ∧ q) ∨ (¬p ∨ ¬q) is a tautology.
10. Determine if [(p ∨ q) ∧ ¬p] → q is a tautology.
11. Check if (p → q) → [(¬q) → (¬p)] is a tautology.
12. Verify if [p ∧ (p → q)] → q is a tautology.
13. Test if (p ∨ q) → (q ∨ p) is a tautology.
14. Determine if [(p → q) ∧ (r → s) ∧ (p ∨ r)] → (q ∨ s) is a tautology.
15. Check if [p ∨ (¬p ∧ q)] ↔ (p ∨ q) is a tautology.
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