Program to check if N is a Star Number

Given an integer N, the task is to check if it is a star number or not.
 

Star number is a centered figurate number that represents a centered hexagram (six-pointed star) similar to Chinese checker game. The first few Star numbers are 1, 13, 37, 73 ...

Examples: 
 

Input: N = 13 
Output: Yes 
Explanation: 
Second star number is 13.
Input: 14 
Output: No 
Explanation: 
Second star number is 13, where as 37 is third. 
Therefore, 14 is not a star number. 
 

Approach: 
 

1. The K^th term of the star number is given as
   K^{th} Term = 6*K*(K-1) + 1       
    
2. As we have to check that the given number can be expressed as a star number or not. This can be checked as follows - 
    

=> N = 6*K*(K-1) + 1       
=> N = 6*K^{2} - 6*K + 1       
=> K = \frac{6 + \sqrt{24*N + 12}}{12}       
 

1. 
    
2. Finally, check the value of computed using this formulae is an integer, which means that N is a star number.

Below is the implementation of the above approach:
 

// C++ implementation to check that
// a number is a star number or not

#include <bits/stdc++.h>

using namespace std;

// Function to check that the
// number is a star number
bool isStar(int N)
{
    float n
        = (6 + sqrt(24 * N + 12))
          / 6;

    // Condition to check if the
    // number is a star number
    return (n - (int)n) == 0;
}

// Driver Code
int main()
{
    int i = 13;

    // Function call
    if (isStar(i)) {
        cout << "Yes";
    }
    else {
        cout << "No";
    }
    return 0;
}

// Java implementation to check that
// a number is a star number or not
import java.io.*; 
import java.util.*; 

class GFG{ 
    
// Function to check that the
// number is a star number
static boolean isStar(int N)
{
    double n = (6 + Math.sqrt(24 * N + 12)) / 6;

    // Condition to check if the
    // number is a star number
    return (n - (int)n) == 0;
}
    
// Driver code
public static void main(String[] args) 
{ 
    int i = 13;

    // Function call
    if (isStar(i))
    {
        System.out.println("Yes");
    }
    else 
    {
        System.out.println("No");
    }
} 
} 

// This code is contributed by coder001

# Python3 implementation to check that 
# a number is a star number or not 
import math

# Function to check that the 
# number is a star number 
def isStar(N):
    
    n = (math.sqrt(24 * N + 12) + 6) / 6
    
    # Condition to check if the 
    # number is a star number
    return (n - int(n)) == 0
    
# Driver Code 
i = 13

# Function call
if isStar(i):
    print("Yes")
else:
    print("No")

# This code is contributed by ishayadav181

// C# implementation to check that
// a number is a star number or not
using System;

class GFG{ 
    
// Function to check that the
// number is a star number
static bool isStar(int N)
{
    double n = (6 + Math.Sqrt(24 * N + 12)) / 6;

    // Condition to check if the
    // number is a star number
    return (n - (int)n) == 0;
}
    
// Driver code
public static void Main() 
{ 
    int i = 13;

    // Function call
    if (isStar(i))
    {
        Console.WriteLine("Yes");
    }
    else
    {
        Console.WriteLine("No");
    }
} 
} 

// This code is contributed by Code_Mech

<script>
// Javascript implementation to check that
// a number is a star number or not

// Function to check that the
// number is a star number
function isStar(N)
{
    let n
        = (6 + Math.sqrt(24 * N + 12))
          / 6;

    // Condition to check if the
    // number is a star number
    return (n - parseInt(n)) == 0;
}

// Driver Code
let i = 13;

// Function call
if (isStar(i)) {
    document.write("Yes");
}
else {
    document.write("No");
}

// This code is contributed by rishavmahato348.
</script>

Yes

Time Complexity: O(logN) because inbuilt sqrt function has been used, which has time complexity O(logN)
Auxiliary Space: O(1)

spp____

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Article Tags :

• Mathematical
• School Programming
• DSA
• series

Practice Tags :

• Mathematical
• series