Program to find Nth term of the series 2, 4, 3, 4, 15...

Last Updated : 04 Aug, 2022

Given a number N. The task is to write a program to find the Nth term in the below series as follows:

2, 4, 3, 4, 15...

Examples:

Input: N = 5
Output: 15
Explanation:
For N = 5,
Nth term = ( N * ( (N%2) + (N%3) ) 
         = ( 5 * ( (5%2) + (5%3) ) 
         = ( 5 * ( 1 + 2 )
         = 15

Input: N = 4 
Output: 4

Generalized Nth term of this series:

Nth term = ( N * ( (N%2) + (N%3) ) )

Below is the implementation of the above approach:

C++

// CPP program to find N-th term of the series:
// 2, 4, 3, 4, 15...

#include <iostream>
using namespace std;

// function to calculate Nth term of series
int nthTerm(int N)
{
    // By using above formula
    return (N * ((N % 2) + (N % 3)));
}

// Driver Function
int main()
{

    // get the value of N
    int N = 5;

    // Calculate and print the Nth term
    cout << "Nth term for N = " << N << " : " << nthTerm(N);

    return 0;
}

Java

import java.io.*;

// Class to calculate Nth term of series
class Nth {
    public int nthTerm(int N)
    {
        // By using above formula
        return (N * ((N % 2) + (N % 3)));
    }
}

// Main class for main method
class GFG {

    public static void main(String[] args)
    {

        // get the value of N
        int N = 5;

        // create object of Class Nth
        Nth a = new Nth();

        // Calculate and print the Nth term
        System.out.println("Nth term for N = " + N + " : "
                           + a.nthTerm(N));
    }
}

Python3

# Python3 program to find N-th term of the series:
# 2, 4, 3, 4, 15...


# function to calculate Nth term of series
def nthTerm(N):

    # By using above formula
    return (N * ((N % 2) + (N % 3)))


# Driver Function


# get the value of N
if __name__ == '__main__':
    N = 5

    # Calculate and print the Nth term
    print("Nth term for N = ", N, " : ", nthTerm(N))

# This code is contributed by ash264

// C# program to find 
// N-th term of the series:
// 2, 4, 3, 4, 15...
using System;

class GFG
{
public int nthTerm(int N)
{
    // By using above formula
    return (N * ((N % 2) + (N % 3)));
}

public static void Main()
{

    // get the value of N
    int N = 5;

    GFG a = new GFG();

    // Calculate and print the Nth term
    Console.Write("Nth term for N = " + 
                            N + " : " + 
                         a.nthTerm(N));
}
}

// This code is contributed 
// by ChitraNayal

PHP

<?php
// PHP program to find 
// N-th term of the series: 
// 2, 4, 3, 4, 15...

function nthTerm($N)
{
    return ($N * (($N % 2) + ($N % 3)));
}

// Driver code
$N = 5 ;

echo "Nth term for N = " . $N . 
          " : " . nthTerm($N) ;

// This code is contributed by ANKITRAI1
?>

JavaScript

<script>
// JavaScript program to find N-th term of the series:
// 2, 4, 3, 4, 15...

// function to calculate Nth term of series
function nthTerm( N)
{
    // By using above formula
    return (N * ((N % 2) + (N % 3)));
}

// Driver Function

    // get the value of N
    let N = 5;

    // Calculate and print the Nth term
    document.write( "Nth term for N = "
         + N +" : "
         + nthTerm(N));

// This code is contributed by todaysgaurav

</script>

Output:

Nth term for N = 5 : 15

Time Complexity: O(1)

Auxiliary Space: O(1) because using constant variables

Analysis of Algorithms

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Program to find Nth term of the series 2, 4, 3, 4, 15...

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