Python | Max/Min of tuple dictionary values
Last Updated :
22 Apr, 2023
Sometimes, while working with data, we can have a problem in which we need to find the min/max of tuple elements that are received as values of dictionary. We may have a problem to get index wise min/max. Let's discuss certain ways in which this particular problem can be solved.
Method #1 : Using tuple() + min()/max() + zip() + values() The combination of above methods can be used to perform this particular task. In this, we just zip together equi index values extracted by values() using zip(). Then find min/max value using respective function. Finally result is returned as index wise max/min values as a tuple.
Python3
# Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
res = tuple(max(x) for x in zip(*test_dict.values()))
# printing result
print("The maximum values from each index is : " + str(res))
Output : The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)}
The maximum values from each index is : (8, 6, 9)
Method #2 : Using tuple() + map() + values() + * operator This is yet another way in which this task can be performed. The difference is that we use map() instead of loop and * operator for zipping the values together.
Python3
# Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
res = tuple(map(min, *test_dict.values()))
# printing result
print("The minimum values from each index is : " + str(res))
Output : The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)}
The minimum values from each index is : (1, 3, 1)
Method #3 : Using max(),keys(),tuple() methods
Approach
- Initiate a for loop to traverse keys of dictionary
- Append the max of each tuple value to output list
- Convert the list to a tuple
- Display tuple
Python3
# Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# Max / Min of tuple dictionary values
x=list(test_dict.keys())
res=[]
for i in x:
res.append(max(test_dict[i]))
res=tuple(res)
# printing result
print("The maximum values from each index is : " + str(res))
OutputThe original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)}
The maximum values from each index is : (6, 8, 9)
Time Complexity : O(N)
Auxiliary Space : O(N)
Method #4: Using list comprehension and tuple()
You can use a list comprehension to iterate over the values of each key in the dictionary and find the maximum value for each index. Then you can convert the resulting list into a tuple.
- Initialize a dictionary named test_dict with key-value pairs where the values are tuples of three integers. The keys are 'gfg', 'is', and 'best'.
- Print the original dictionary by using the print() function and converting the dictionary to a string using the str() function.
- Create a list comprehension that iterates through each key in the test_dict dictionary.
- For each key, call the max() function on the tuple value associated with that key to find the maximum value in the tuple.
- Add each maximum value to a new list called res.
- Convert the res list to a tuple using the tuple() function.
- Print the result by using the print() function and converting the tuple to a string using the str() function. The result is the maximum value from each index of the tuples in the test_dict dictionary.
Python3
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
# Max / Min of tuple dictionary values using Method #4
res = [max(test_dict[key]) for key in test_dict]
res = tuple(res)
# printing result
print("The maximum values from each index is : " + str(res))
OutputThe original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)}
The maximum values from each index is : (6, 8, 9)
Time complexity: O(nm), where n is the number of keys in the dictionary and m is the length of the tuples.
Auxiliary space: O(n), where n is the number of keys in the dictionary.
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