Python | Pattern Generation using time() module

# Print triangles by giving the number of stars:

# For Diamond, an odd number of stars will give a better result,
# If the number is even then for diamond pattern,
# it will automatically do (row + 1):

import time

n = 5

print("----------Right Angled Triangle Type 1----------")

def right_angle_triangle1(n):
    
    for i in range(1, n + 1):
        for j in range(i):
            time.sleep(0.05)
            print("*", end ="")
        print()
     
right_angle_triangle1(n)

print()

print("----------Right Angled Triangle Type 2----------")

def right_angle_triangle2(n):
    
    for i in range(1, n + 1):
        for j in range(n-i):
            time.sleep(0.05)
            print(" ", end ="")
        for k in range(i):
            time.sleep(0.05)
            print("*", end ="")
        print()
right_angle_triangle2(n)

print()

print("----------Equilateral Triangle----------")

def equilateral_triangle(n):
    
    for i in range(1, n + 1):
        for j in range(n-i):
            time.sleep(0.05)
            print(" ", end ="")
        for k in range(2 * i-1):
            time.sleep(0.05)
            print("*", end ="")
        print()
equilateral_triangle(n)

print()

print("----------Square----------")

def square(n):
    
    for i in range(1, n + 1):
        for j in range(1, n + 1):
            time.sleep(0.05)
            print("*", end ="")
        print()
square(n)

print()

print("----------Diamond----------")

def diamond(n):
    
    cell = n//2 + 1
    for i in range(1, cell + 1): 
        for j in range(cell-i):     
            time.sleep(0.05)
            print(" ", end ="")
        for k in range(2 * i-1):
            time.sleep(0.05)
            print("*", end ="")
        print()

    for i in range(cell-1, 0, -1):
        for j in range(cell-i):
            time.sleep(0.05)
            print(" ", end ="")
            
        for k in range(2 * i-1):
            time.sleep(0.05)
            print("*", end ="")
        print()
diamond(n)