C Storage Classes and Type Qualifiers

Consider the following code:

int a, b, c = 0;

void prtFun(void);

void main()
{
    static int a = 1;
    prtFun();
    a += 1;
    prtFun() printf("\n %d %d ", a, b);
}

void prtFun(void)
{
    static int a = 2;
    int b = 1;
    a += ++b;
    printf("\n %d %d ", a, b);
}

What output will be generated by the given code d\\segment if: 
Line 1 is replaced by “auto int a = 1;” 
Line 2 is replaced by “register int a = 2;” (GATE CS 2012) 

In C, static storage class cannot be used with:

If only one memory location is to be reserved for a class variable, no matter how many objects are instantiated, then the variable should be declared as 

What is the output of the following program? 
 

#include 
int tmp=20;
main( )
{
printf("%d ",tmp);
func( );
printf("%d ",tmp);
}
func( )
{
static int tmp=10;
printf("%d ",tmp);
}

Which of the following is not a storage class specifier in C?

Consider the following pseudocode:

 x : integer := 1
 y : integer := 2
 procedure add
 x := x + y

 procedure second (P: procedure)
 x : integer := 2
 P()
 procedure first
 y : integer := 3
 second(add)
 first()
 write_integer (x)

What does it print if the language uses dynamic scoping with deepbinding?

Consider the following code fragment void foo(int x, int y) { x+=y; y+=x; } main() { int x=5.5; foo(x,x); } What is the final value of x in both call by value and call by reference, respectively?

The following program

main()
{
inc(); inc(); inc();
}
inc()
{
static int x;
printf("%d", ++x);
}