Templates and Generic Programming

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Question 1

Which of the following is true about templates.

  1. Template is a feature of C++ that allows us to write one code for different data types.
  2. We can write one function that can be used for all data types including user defined types. Like sort(), max(), min(), ..etc.
  3. We can write one class or struct that can be used for all data types including user defined types. Like Linked List, Stack, Queue ..etc.
  4. Template is an example of compile time polymorphism.

  • 1 and 2

  • 1, 2 and 3

  • 1, 2 and 4

  • 1, 2, 3 and 4

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Question 2

Predict the output?

C 
#include <iostream>
using namespace std;

template <typename T>
void fun(const T&x)
{
    static int count = 0;
    cout << "x = " << x << " count = " << count << endl;
    ++count;
    return;
}

int main()
{
    fun<int> (1); 
    cout << endl;
    fun<int>(1); 
    cout << endl;
    fun<double>(1.1);
    cout << endl;
    return 0;
}

  • x = 1 count = 0

    x = 1 count = 1

    x = 1.1 count = 0
  • x = 1 count = 0

    x = 1 count = 0

    x = 1.1 count = 0
  • x = 1 count = 0

    x = 1 count = 1

    x = 1.1 count = 2

  • Compiler Error

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Question 3

C 
#include <iostream>
using namespace std;

template <typename T>
T max(T x, T y)
{
    return (x > y)? x : y;
}
int main()
{
    cout << max(3, 7) << std::endl;
    cout << max(3.0, 7.0) << std::endl;
    cout << max(3, 7.0) << std::endl;
    return 0;
}

  • 7
7.0
7.0
  • Compiler Error in all cout statements as data type is not specified.
  • Compiler Error in last cout statement as call to max is ambiguous.
  • None of the above
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Question 4

Output of following program? CPP 
#include <iostream>
using namespace std;

template <class T>
class Test
{
private:
    T val;
public:
    static int count;
    Test()  {   count++;   }
};

template<class T>
int Test<T>::count = 0;

int main()
{
    Test<int> a;
    Test<int> b;
    Test<double> c;
    cout << Test<int>::count   << endl;
    cout << Test<double>::count << endl;
    return 0;
}

  • 0
0
  • 1
1
  • 2
1
  • 1
0
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Question 5

Output of following program? Assume that the size of char is 1 byte and size of int is 4 bytes, and there is no alignment done by the compiler. CPP 
#include<iostream>
#include<stdlib.h>
using namespace std;

template<class T, class U>
class A  {
    T x;
    U y;
    static int count;
};

int main()  {
   A<char, char> a;
   A<int, int> b;
   cout << sizeof(a) << endl;
   cout << sizeof(b) << endl;
   return 0;
}

  • 6
12
  • 2
8
  • Compiler Error: There can not be more than one template arguments.
  • 8
8
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Question 6

Output of following program? Assume that the size of int is 4 bytes and size of double is 8 bytes, and there is no alignment done by the compiler. C 
#include<iostream>
#include<stdlib.h>
using namespace std;

template<class T, class U, class V=double>
class A  {
    T x;
    U y;
    V z;
    static int count;
};

int main()
{
   A<int, int> a;
   A<double, double> b;
   cout << sizeof(a) << endl;
   cout << sizeof(b) << endl;
   return 0;
}

  • 16
24
  • 8
16
  • 20
28
  • Compiler Error: template parameters cannot have default values.
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Question 7

Output of following program.

CPP 
#include <iostream>
using namespace std;

template <class T, int max>
int arrMin(T arr[], int n)
{
   int m = max;
   for (int i = 0; i < n; i++)
      if (arr[i] < m)
         m = arr[i];

   return m;
}

int main()
{
   int arr1[]  = {10, 20, 15, 12};
   int n1 = sizeof(arr1)/sizeof(arr1[0]);

   char arr2[] = {1, 2, 3};
   int n2 = sizeof(arr2)/sizeof(arr2[0]);

   cout << arrMin<int, 10000>(arr1, n1) << endl;
   cout << arrMin<char, 256>(arr2, n2);
   return 0;
}

  • Compiler error, template argument must be a data type.

  • 10
    1
  • 10000
    256
  • 1
    1
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Question 8

What will be the output of the following C++ code?

#include <iostream>
   using namespace std;
   template <class T>
   T max (T& a, T& b)
   {
       return (a>b?a:b);
   }
   int main ()
   {
       int i = 5, j = 6, k;
       long l = 10, m = 5, n;
       k = max(i, j);
       n = max(l, m);
       cout << k << endl;
       cout << n << endl;
       return 0;
   }

  • 6

  • 6
10
  • 5
10

  • 5

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