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Last Updated: 27 June 2024
C++ doesn't have built-in functionality of interfaces like other programming languages such as Java. However, interfaces can be implemented in C++ using the abstract class...
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C++ | Inheritance | Question 14
Last Updated: 28 June 2021
Consider the below C++ program.[sourcecode language="C"]#includeiostreamusing namespace std;class A{public: A(){ cout 1;} A(const A obj){ cout 2;}};class B: virtua...
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C++ | Inheritance | Question 13
Last Updated: 28 June 2021
[sourcecode language="CPP"]#includeiostreamusing namespace std;class Base1{public: char c;};class Base2{public: int c;};class Derived: public Base1, public Base2{pub...
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C++ | Inheritance | Question 12
Last Updated: 28 June 2021
[sourcecode language="CPP"]#includeiostreamusing namespace std;class Base{protected: int a;public: Base() {a = 0;}};class Derived1: public Base{public: int c;};c...
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C++ | Inheritance | Question 11
Last Updated: 28 June 2021
[sourcecode language="C"]#includeiostreamusing namespace std;class Base{public : int x, y;public: Base(int i, int j){ x = i; y = j; }};class Derived : public Base{pu...
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C++ | Inheritance | Question 10
Last Updated: 28 June 2021
Output of following program?[tabby title="CPP"][sourcecode language="cpp"]#include #includeusing namespace std;class Base{public: virtual string print() const { ...
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C++ | Inheritance | Question 9
Last Updated: 01 June 2021
[sourcecode language="C"]#includeiostreamusing namespace std;class Base {public: void fun() { cout Base::fun() called; } void fun(int i) { cou...
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C++ | Inheritance | Question 8
Last Updated: 28 June 2021
[tabby title="C"][sourcecode language="c"]#includeusing namespace std;class Base{public: int fun() { cout << \"Base::fun() called\"; } int fun(int i) { cout << \"B...
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