time.Milliseconds() Function in Golang With Examples

time.Microseconds() Function in Golang With Examples

Last Updated : 21 Apr, 2020

In Go language, time packages supplies functionality for determining as well as viewing time. The Microseconds() function in Go language is used to find the duration of time in form of an integer microsecond count. Moreover, this function is defined under the time package. Here, you need to import the “time” package in order to use these functions.

Syntax:

func (d Duration) Microseconds() int64

Here, d is the duration of time.

Return Value: It returns the duration value as int64.

Example 1:

// Golang program to illustrate the usage of 
// Microseconds() function 
  
// Including main package 
package main 
  
// Importing fmt and time 
import ( 
    "fmt"
    "time"
) 
  
// Calling main 
func main() { 
  
    // Defining duration  
    // of Microseconds method 
    micr, _ := time.ParseDuration("5m") 
  
    // Prints duration as  
    // an integer microsecond 
    fmt.Printf("Only %d Microseconds of task "+ 
          "is remaining.", micr.Microseconds()) 
} 

Output:

Only 300000000 Microseconds of task is remaining.

Example 2:

// Golang program to illustrate the usage of 
// Microseconds() function 
  
// Including main package 
package main 
  
// Importing fmt and time 
import ( 
    "fmt"
    "time"
) 
  
// Calling main 
func main() { 
  
    // Defining duration of Microseconds method 
    micr, _ := time.ParseDuration("1m1s576ms46ns") 
  
    // Prints duration as  
    // an integer microsecond 
    fmt.Printf("Only %d Microseconds of "+ 
     "task is remaining.", micr.Microseconds()) 
} 

Output:

Only 61576000 Microseconds of task is remaining.

time.Milliseconds() Function in Golang With Examples

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