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www dot query at gmail dot com
13 years ago
$image->annotateImage($draw, 10, 45, 0, 'The quick brown fox');

If the third parameter, the 'Y' value, is 0, the text will be invisible because the text is printed ABOVE the image - not on the image.

The solution is to start, depending on your chosen font size, with a Y value of about 40 and experiment.

[Also:]

When wishing to print some text on a photograph and make that text sufficiently contrasting to the background image, use a 4 byte code for colour and transparency.

It is the same 4 byte code using by the parameter '-undercolor' in ImageMagick's command lime instruction 'convert'.

The first 3 bytes are the RGB colour code and the fourth byte is the transparency byte.

<?php
$picin
= new Imagick($pic1);
$picin->scaleimage(800,0);
$height = $picin->getimageheight();

$draw = new ImagickDraw();
$draw->setFillColor('#ffff00');
$draw->setFont('Eurostile');
$draw->setFontSize(21);
$draw->setTextUnderColor('#ff000088');
$picin->annotateImage($draw,40,$height-10,0,"Hallo");

$picin->writeimage($pic6);
?>

The example code produces yellow text on a semi-transparent red background.

$pic1 and $pic6 were previously defined as directory/file strings.

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