The t results
The t results
Let tan
2
t


The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t


The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t 
The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t ;
2
tanIf

t
2
1
2
tan
t
t


The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t ;
2
tanIf

t
2
1
2
tan
t
t

 2
1
2
sin
t
t


The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t ;
2
tanIf

t
2
1
2
tan
t
t

 2
1
2
sin
t
t

 2
2
1
1
cos
t
t



The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t ;
2
tanIf

t
2
1
2
tan
t
t

 2
1
2
sin
t
t

 2
2
1
1
cos
t
t



Note:
If tan ;t  2
2
tan 2
1
t
t
 

The t results
Let tan
2
t


2
2tan
2tan
1 tan
2





2
1
2
tan
t
t



t2
2
1 t
2
1 t
   
222 2
2 1h t t  
2 2 4
4 1 2t t t   
4 2
2 1t t  
 
22
1t ;
2
tanIf

t
2
1
2
tan
t
t

 2
1
2
sin
t
t

 2
2
1
1
cos
t
t



Note:
If tan ;t  2
2
tan 2
1
t
t
 

If tan 2 ;t  2
2
tan 4
1
t
t
 

 
1 cos
e.g. i Show that , where tan
sin 2
x x
t t
x

 
 
1 cos
e.g. i Show that , where tan
sin 2
x x
t t
x

 
1 cos
sin
x
x

2
2
2
1
1
1
2
1
t
t
t
t




is double ,
2
so results can be used for sin ,cos
x
x
t x x
 
 
 
 
 
1 cos
e.g. i Show that , where tan
sin 2
x x
t t
x

 
1 cos
sin
x
x

2
2
2
1
1
1
2
1
t
t
t
t




is double ,
2
so results can be used for sin ,cos
x
x
t x x
 
 
 
 
 2 2
1 1
2
t t
t
  

 
1 cos
e.g. i Show that , where tan
sin 2
x x
t t
x

 
1 cos
sin
x
x

2
2
2
1
1
1
2
1
t
t
t
t




is double ,
2
so results can be used for sin ,cos
x
x
t x x
 
 
 
 
 2 2
1 1
2
t t
t
  

2
2
2
t
t

t
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
Let tan ;
2
t


1 sin cos
1 sin cos
 
 
 
 
2
2 2
2
2 2
2 1
1
1 1
2 1
1
1 1
t t
t t
t t
t t

 
 

 
 
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
Let tan ;
2
t


1 sin cos
1 sin cos
 
 
 
 
2
2 2
2
2 2
2 1
1
1 1
2 1
1
1 1
t t
t t
t t
t t

 
 

 
 
 2 2
2 2
1 2 1
1 2 1
t t t
t t t
   

   
  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
Let tan ;
2
t


1 sin cos
1 sin cos
 
 
 
 
2
2 2
2
2 2
2 1
1
1 1
2 1
1
1 1
t t
t t
t t
t t

 
 

 
 
 2 2
2 2
1 2 1
1 2 1
t t t
t t t
   

   
2
2 2
2 2
t t
t



  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
Let tan ;
2
t


1 sin cos
1 sin cos
 
 
 
 
2
2 2
2
2 2
2 1
1
1 1
2 1
1
1 1
t t
t t
t t
t t

 
 

 
 
 2 2
2 2
1 2 1
1 2 1
t t t
t t t
   

   
2
2 2
2 2
t t
t



 
 
2 1
2 1
t t
t



  2
2tan75
ii Use tan to simplify
2 1 tan 75
t





Let tan75 ;t  
i.e. 75
2

 
150  
2
2tan75
1 tan 75

 2
2
1
t
t


sin
sin150 
1
2

 
1 sin cos
iii Prove tan
1 sin cos 2
  
 
 

 
Let tan ;
2
t


1 sin cos
1 sin cos
 
 
 
 
2
2 2
2
2 2
2 1
1
1 1
2 1
1
1 1
t t
t t
t t
t t

 
 

 
 
 2 2
2 2
1 2 1
1 2 1
t t t
t t t
   

   
2
2 2
2 2
t t
t



 
 
2 1
2 1
t t
t



t tan
2


2005 Extension 1 HSC Q4b)
(iv) By making the substitution tan or otherwise,
2
show that cosec cot cot
2
t


 

 
2005 Extension 1 HSC Q4b)
(iv) By making the substitution tan or otherwise,
2
show that cosec cot cot
2
t


 

 
cosec cot 
2 2
1 1
2 2
t t
t t
 
 
2005 Extension 1 HSC Q4b)
(iv) By making the substitution tan or otherwise,
2
show that cosec cot cot
2
t


 

 
cosec cot 
t
t
1
2
2


2 2
1 1
2 2
t t
t t
 
 
2005 Extension 1 HSC Q4b)
(iv) By making the substitution tan or otherwise,
2
show that cosec cot cot
2
t


 

 
cosec cot 
t
t
1
2
2


2
cot


2 2
1 1
2 2
t t
t t
 
 
2005 Extension 1 HSC Q4b)
(iv) By making the substitution tan or otherwise,
2
show that cosec cot cot
2
t


 

 
cosec cot 
t
t
1
2
2


2
cot


2 2
1 1
2 2
t t
t t
 
 
Exercise 2B; 1def, 3ace, 4bcf, 5aceg, 6, 8bd, 10a

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11 x1 t01 02 binomial products (2014)
12 x1 t02 01 differentiating exponentials (2014)
11 x1 t01 01 algebra & indices (2014)
12 x1 t01 03 integrating derivative on function (2013)
12 x1 t01 02 differentiating logs (2013)
12 x1 t01 01 log laws (2013)
X2 t02 04 forming polynomials (2013)
X2 t02 03 roots & coefficients (2013)
X2 t02 02 multiple roots (2013)
X2 t02 01 factorising complex expressions (2013)
11 x1 t16 07 approximations (2013)
11 x1 t16 06 derivative times function (2013)
11 x1 t16 05 volumes (2013)
11 x1 t16 04 areas (2013)
11 x1 t16 03 indefinite integral (2013)
11 x1 t16 02 definite integral (2013)
11 x1 t16 01 area under curve (2013)
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11 x1 t08 05 t results (2013)

  • 2. The t results Let tan 2 t  
  • 3. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t  
  • 4. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t
  • 5. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t 
  • 6. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t ; 2 tanIf  t 2 1 2 tan t t  
  • 7. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t ; 2 tanIf  t 2 1 2 tan t t   2 1 2 sin t t  
  • 8. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t ; 2 tanIf  t 2 1 2 tan t t   2 1 2 sin t t   2 2 1 1 cos t t   
  • 9. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t ; 2 tanIf  t 2 1 2 tan t t   2 1 2 sin t t   2 2 1 1 cos t t    Note: If tan ;t  2 2 tan 2 1 t t   
  • 10. The t results Let tan 2 t   2 2tan 2tan 1 tan 2      2 1 2 tan t t    t2 2 1 t 2 1 t     222 2 2 1h t t   2 2 4 4 1 2t t t    4 2 2 1t t     22 1t ; 2 tanIf  t 2 1 2 tan t t   2 1 2 sin t t   2 2 1 1 cos t t    Note: If tan ;t  2 2 tan 2 1 t t    If tan 2 ;t  2 2 tan 4 1 t t   
  • 11.   1 cos e.g. i Show that , where tan sin 2 x x t t x   
  • 12.   1 cos e.g. i Show that , where tan sin 2 x x t t x    1 cos sin x x  2 2 2 1 1 1 2 1 t t t t     is double , 2 so results can be used for sin ,cos x x t x x        
  • 13.   1 cos e.g. i Show that , where tan sin 2 x x t t x    1 cos sin x x  2 2 2 1 1 1 2 1 t t t t     is double , 2 so results can be used for sin ,cos x x t x x          2 2 1 1 2 t t t    
  • 14.   1 cos e.g. i Show that , where tan sin 2 x x t t x    1 cos sin x x  2 2 2 1 1 1 2 1 t t t t     is double , 2 so results can be used for sin ,cos x x t x x          2 2 1 1 2 t t t     2 2 2 t t  t
  • 15.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t     
  • 16.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t  
  • 17.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150  
  • 18.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t  
  • 19.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin
  • 20.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2 
  • 21.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2          
  • 22.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2           Let tan ; 2 t   1 sin cos 1 sin cos         2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 t t t t t t t t          
  • 23.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2           Let tan ; 2 t   1 sin cos 1 sin cos         2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 t t t t t t t t            2 2 2 2 1 2 1 1 2 1 t t t t t t         
  • 24.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2           Let tan ; 2 t   1 sin cos 1 sin cos         2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 t t t t t t t t            2 2 2 2 1 2 1 1 2 1 t t t t t t          2 2 2 2 2 t t t   
  • 25.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2           Let tan ; 2 t   1 sin cos 1 sin cos         2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 t t t t t t t t            2 2 2 2 1 2 1 1 2 1 t t t t t t          2 2 2 2 2 t t t        2 1 2 1 t t t   
  • 26.   2 2tan75 ii Use tan to simplify 2 1 tan 75 t      Let tan75 ;t   i.e. 75 2    150   2 2tan75 1 tan 75   2 2 1 t t   sin sin150  1 2    1 sin cos iii Prove tan 1 sin cos 2           Let tan ; 2 t   1 sin cos 1 sin cos         2 2 2 2 2 2 2 1 1 1 1 2 1 1 1 1 t t t t t t t t            2 2 2 2 1 2 1 1 2 1 t t t t t t          2 2 2 2 2 t t t        2 1 2 1 t t t    t tan 2  
  • 27. 2005 Extension 1 HSC Q4b) (iv) By making the substitution tan or otherwise, 2 show that cosec cot cot 2 t       
  • 28. 2005 Extension 1 HSC Q4b) (iv) By making the substitution tan or otherwise, 2 show that cosec cot cot 2 t        cosec cot  2 2 1 1 2 2 t t t t    
  • 29. 2005 Extension 1 HSC Q4b) (iv) By making the substitution tan or otherwise, 2 show that cosec cot cot 2 t        cosec cot  t t 1 2 2   2 2 1 1 2 2 t t t t    
  • 30. 2005 Extension 1 HSC Q4b) (iv) By making the substitution tan or otherwise, 2 show that cosec cot cot 2 t        cosec cot  t t 1 2 2   2 cot   2 2 1 1 2 2 t t t t    
  • 31. 2005 Extension 1 HSC Q4b) (iv) By making the substitution tan or otherwise, 2 show that cosec cot cot 2 t        cosec cot  t t 1 2 2   2 cot   2 2 1 1 2 2 t t t t     Exercise 2B; 1def, 3ace, 4bcf, 5aceg, 6, 8bd, 10a