![Problem20Match the complexes in Column-I with their properties listed in Column-II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS Column-I Column-II(A) [Co(NH3)4(H2O) 2]Cl2 (p) geometrical isomers(B) [Pt(NH3) 2Cl2] (q) paramagnetic(C) [Co(H2O)5Cl]Cl (r) diamagnetic(D) [Ni(H2O)6]Cl2 (s) metal ion with +2 oxidation state](https://image.slidesharecdn.com/chemistry-2007i-110913035938-phpapp02/85/IITJEE-Chemistry-2007-27-320.jpg)
IITJEE Chemistry 2007
- 1. IIT JEE –Past papersCHEMISTRY- UNSOLVED PAPER - 2007
- 2. SECTION – ISingle Correct Answer TypeThis section contains 9 multiple choice questions numbered 1 to 9. Each question has 4 choices (A), (B), (C) and (D), out of which only one is correct.
- 3. 01ProblemThe number of structural isomers for C6H14 is3 45 6
- 4. Problem02In the following reaction,the structure of the major product ‘X’ is b.c. d.
- 5. Problem03When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol−1), a freezing point depression of 2 K is observed. The van’t Hoff factor (i) is0.5 1 2 3
- 6. Problem04Among the following, the paramagnetic compound isNa2 O2 O3N2 O KO2
- 7. Problem05The value of log10 K for a reaction A B is(Given : ∆rH0298K 54.07kJ mol , ∆rSS0298K 10JK-1 mol-1 and − R= 8.314 JK-1 mol-1 2.303×8.314×298 = 5705)510 95 100
- 8. Problem06The species having bond order different from that in CO isNO− NO+CN − N2
- 9. Problem07The percentage of p-character in the orbitals forming P−P bonds in P4 is25335075
- 10. 08ProblemExtraction of zinc from zinc blende is achieved byelectrolytic reduction roasting followed by reduction with carbonroasting followed by reduction with another metal roasting followed by self-reduction
- 11. Problem09The reagent(s) for the following conversionalcoholic KOH alcoholic KOH followed by NaNH2aqueous KOH followed by NaNH2Zn/CH3OH
- 12. SECTION – IIAssertion - Reason TypeThis section contains 4 questions numbered 10 to 13. Each question contains STATEMENT-1 (Assertion) and STATEMENT-2 (Reason). Each question has 4 choices (A), (B), (C) and (D) out of which ONLY ONE is correct.
- 13. Problem10STATEMENT-1: p-Hydroxybenzoic acid has a lower boiling point than o-hydroxybenzoic acid. becauseSTATEMENT-2: o-Hydroxybenzoic acid has intramolecular hydrogen bonding.a. Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.b. Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.Statement-1 is True, Statement -2 is False. Statement-1 is False, Statement-2 is True.
- 14. Problem11STATEMENT-1: Micelles are formed by surfactant molecules above the critical micellar concentration (CMC).becauseSTATEMENT-2: The conductivity of a solution having surfactant molecules decreases sharply at the CMC.a. Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.b. Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.c. Statement-1 is True, Statement-2 is False.d. Statement-1 is False, Statement-2 is True.
- 15. 12ProblemSTATEMENT-1: Boron always forms covalent bond.becauseSTATEMENT-2: The small size of B3+ favours formation of covalent bond.a. Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.b. Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.c. Statement-1 is True, Statement-2 is True.d. Statement-1 is False, Statement-2 is True.
- 16. Problem13STATEMENT-1: In water, orthoboric acid behaves as a weak monobasic acid.becauseSTATEMENT-2: In water, orthoboric acid acts as a proton donor.a. Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.b. Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.c. Statement-1is True, Statement-2 is False.d. Statement-1 is False, Statement-2 is True.
- 17. SECTION – IIILinked Comprehension Type This section contains 2 paragraphs P14-16 and P17-19. Based upon each paragraph, 3 multiple choice questions have to be answered. Each question has 4 choices (A), (B), (C) and (D), out of which ONLY ONE is correct.
- 18. Paragraph for Question Nos. 1 4 to 16Chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules (approximately 6.023 × 1023) are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced. This concept has implications in diverse areas such as analytical chemistry, biochemistry, electrochemistry and radiochemistry. The following example illustrates a typical case, involving chemical/electrochemical reaction, which requires a clear understanding of the mole concept. A 4.0 molar aqueous solution of NaCl is prepared and 500 mL of this solution is electrolyzed. This leads to the evolution of chlorine gas at one of the electrodes (atomic mass: Na = 23, Hg = 200; 1 Faraday=96500 coulombs)
- 19. Problem14The total number of moles of chlorine gas evolved is0.5 1.02.0 3.0
- 20. Problem15If the cathode is a Hg electrode, the maximum weight (g) of amalgam formed from this solution is200 225400 446
- 21. Problem16The total charge (coulombs) required for complete electrolysis is241254825096500 193000
- 22. Paragraph for Question Nos. 17 and 19The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other interatomic interactions.The direct reaction of xenon with fluorine leads to a series of compounds with oxidation numbers +2, +4 and +6. XeF4 reacts violently with water to give XeO3. The compounds of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell.
- 23. 17ProblemArgon is used in arc welding because of itslow reactivity with metal ability to lower the melting point of metal Flammabilityhigh calorific value
- 24. Problem18The structure of XeO3 islinear planarpyramidal T-shaped
- 25. Problem19XeF4 and XeF6 are expected to beoxidizing reducingUncreativestrongly basic
- 26. SECTION – IVMatrix-Match TypeThis section contains 3 questions. Each question contains statements given in two columns which have to be matched. Statements (A, B, C, D) in column I have to be matched with statements (p, q, r, s) in column II. The answers to these questions have to be appropriately bubbled as illustrated in the following example.If the correct match are A-p, A-s, B-r, C-p, C-q and D-s, then the correctly bubbled 4 × 4 matrix should be as follows:
- 27. Problem20Match the complexes in Column-I with their properties listed in Column-II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS Column-I Column-II(A) [Co(NH3)4(H2O) 2]Cl2 (p) geometrical isomers(B) [Pt(NH3) 2Cl2] (q) paramagnetic(C) [Co(H2O)5Cl]Cl (r) diamagnetic(D) [Ni(H2O)6]Cl2 (s) metal ion with +2 oxidation state
- 28. Problem21Match gases under specified conditions listed in Column-I with their properties/laws in Column-II. Indicate your answer by darkening the appropriate bubsbles of the 4 × 4 matrix given in the ORS. Column-I Column-II(A) hydrogen gas (P = 200 atm, T = 273K) (p) compressibility factor ≠ 1(B) hydrogengas (P ∼ 0, T = 273K) (q) attractive forces are dominant(C) CO2 (P = 1 atm, T = 273K) (r) PV = nRT(D) real gas with very large molar volume (s) P(V − nb) = nRT
- 29. Problem22Match the chemical substances in Column-I with type of polymers/type of bonds in Column-II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS. Column-I Column-II(A) cellulose (p) natural polymer(B) nylon-6, 6 (q) synthetic polymer(C) Protein (r) amide linkage(D) Sucrose (s) glycoside linkage
- 30. FOR SOLUTION VISIT WWW.VASISTA.NET