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P7 waveform
This document discusses sinusoidal waveforms and solving for properties of an alternating current. It defines periodic time and peak-to-peak voltage for sinusoidal waves. It shows that a shifted waveform is represented by an expression with a phase angle added to or subtracted from the angular frequency term. As an example, it is given that i = 30 sin(100πt + 0.27) amperes, and it solves this to find the amplitude of 30 amperes, periodic time of 0.02 seconds (frequency of 50Hz), phase angle of 0.27 radians (15.46 degrees), and angular frequency ω of 100π.
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P7 waveform
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- 2. T = PeriodicTime EP-P = Peak to peak voltage
- 6. ftAtA mm 2sinsin
- 7. )sin( tAm If the waveform is shifted to the right or left, the expression becomes:
- 10. An alternatingcurrent is given by i = 30 sin(100πt + 0.27) amperes. Find the amplitude, periodic time, frequency and phase angle. i = 30 sin(100πt + 0.27) i = A sin (ωt + Θ) Amplitude A = 30A phase angle Θ = 0.27rads = 15.46 ω = 2fπ = 100π, frequency f = 50Hz T = 1/f = 1/50 = 0.02s