8085 Program to Add Two 8-Bit Numbers

In this program, we will see how to add two 8-bit numbers using 8085 microprocessor.

Problem Statement

Write 8085 Assembly language program to add two 8-bit numbers and store the result at locations 8050H and 8051H.

Discussion

To perform this task, we are using the ADD operation of 8085 Microprocessor. When the result of the addition is the 1-byte result, then the carry flag will not be enabled. When the result is exceeding the 1-byte range, then the carry flag will be 1

We are using two numbers at location 8000H and 8001H. When the numbers are 6CH and 24H, then the result will be (6C + 24 = 90) and when the numbers are FCH and 2FH, then the result will be (FC + 2F = 12B) Here the result is exceeding the range of 1-byte.

Input

first input

Address
 Data
.
.
.
 .
.
.
8000
 6C
8001
 24
.
.
.
 .
.
.

second input

Address
 Data
.
.
.
 .
.
.
8000
 FC
8001
 2F
.
.
.
 .
.
.

Flow Diagram


Program

Address
 HEX Codes
 Labels
 Mnemonics
 Comments
F000
 0E,00

MVIC,00H
 Clear C register
F002
 21,00, 80

LXIH,8000H
 Load initial address to get operand
F005
 7E

MOVA, M
 Load Acc with a memory element
F006
 23

INX H
 Point to next location
F007
 46

MOVB, M
 Load B with the second operand
F008
 80

SUB B
 Add B with A
F009
 D2,0D, F0

JNC STORE
 When CY = 0, go to STORE
F00C
 0C

INR C
 Increase C by 1
F00D
 21,50, 80
 STORE
 LXIH,8050H
 Load the destination address
F010
 77

MOVM, A
 Store the result
F011
 23

INX H
 Point to next location
F012
 71

MOVM, C
 Store the carry
F013
 76

HLT
 Terminate the program

Output

first output

Address
 Data
.
.
.
 .
.
.
8050
 90
8051
 00
.
.
.
 .
.
.

second output

Address
 Data
.
.
.
 .
.
.
8050
 2B
8051
 01
.
.
.
 .
.
.
Updated on: 2023-10-07T02:53:58+05:30

37K+ Views

Kickstart Your Career

Get certified by completing the course

Get Started
Advertisements